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goldfiish [28.3K]
3 years ago
5

Use the given line(s) from a random number table to select numbers to use in each problem. Select 2 contestants for a game show

out of a pool of 50 46547 17395 25765 11325 14071 61688
A. 39, 25

B. 46, 47

C. 4, 6

D. 46, 25
Mathematics
2 answers:
Mazyrski [523]3 years ago
7 0
46, 54, 71, 73, 95, 25, 76, 51, 13, 25, 14, 07, 16, 16, 88

From the numbers and the options 2 number between 01 and 50 is 46 and 25.
ivolga24 [154]3 years ago
4 0

Answer:

D. 46, 25

Step-by-step explanation:

You want to select numbers between 1 and 50. Starting from the beginning of the random number table, the first number is 46, pick it. The next numbers are:

54 - skip it

71 - skip it

73 - skip it

95 - skip it

25 - pick it

All the skipped numbers are greater than 50, and the picked numbers are between 1 and 50.

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Answer:

126 $

Step-by-step explanation:

1- 18000 / 100 = 180

2- 180 x 0.7 = 126$

7 0
3 years ago
Read 2 more answers
4. What is the slope of the line through the points (2, 5) and (6, 13)?
julsineya [31]

the slope of the line is 2

4 0
3 years ago
Can someone help me with my work
DENIUS [597]

For all of these problems, make equation into slope-intercept form to be able to see what the slope is.

answer to 1.d. is neither

4 0
3 years ago
Solve x^2-6x+25 = 0 by completing the square.
Oksana_A [137]

First, subtract both sides by 25:

x^2 - 6x = -25

Because we're completing the square, we subtract both sides by 9:

x^2 - 6x - 9 = -34

(x - 3) = 5.831 (about)

x = 8.831

3 0
3 years ago
Jen Butler has been pricing​ Speed-Pass train fares for a group trip to New York. Three adults and four children must pay $ 79.
xxMikexx [17]

<u>Answer:</u>

Price of the​ adult's ticket = $13

Price of a​ child's ticket = $ 10

<u>Step-by-step explanation:</u>

Given:

Cost of train fares for Three adults and four children = $79

Cost of train fares Two adults and three children  = $ 56

To Find:

Price of the​ adult's ticket and the price of a​ child's ticket =?

Solution:

Let the cost of one adult's ticket be x  and

Let the cost of one child's ticket be y

Then

Three adults and four children must pay $ 79 be

3x + 4y = 79-----------------------------------------------(1)

Two adults and three children must pay $56

2x + 3y = 56----------------------------------------------(2)

multiply  eq(1) by 2, we get

6x + 8y = 158----------------------(3)

multiply  eq(2) by 3, we get

6x + 9y = 168----------------------(4)

Subracting (3) from (4)

 6x + 9y = 168

 6x + 8y = 158

(-)      (-)       (-)

------------------------------

0x +  y = 10

------------------------------

y=10

Now substitute the value of y in eq (1) to get the value of x

3x + 4(10)= 79

3x +  40 = 79

3x = 79 - 40

3x = 39

x = \frac{39}{3}

x= 13

3 0
3 years ago
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