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svetoff [14.1K]
3 years ago
14

3/16=(-5/4)+g please help me

Mathematics
1 answer:
Alla [95]3 years ago
6 0

Answer:

g=\frac{23}{16}

Step-by-step explanation:

To begin you want to isolate the g. So you add \frac{5}{4} to both sides. On the left is cancels out so it looks like this:

\frac{3}{16} +\frac{5}{4} =g

Next, you find the Least Common Denominator (LCD) which is 16. And since one fraction already has a denominator of 16 you leave it as it is. The other fraction, however, needs to be multiplied (both top and bottom) by 4 to get the denominator (bottom) to 16. So:

\frac{3}{16} +(\frac{5}{4}*\frac{4}{4} ) =g

Multiplying it out you get:

\frac{3}{16} +\frac{20}{16} =g

Lastly, just add across:

\frac{3+20}{16} =\frac{23}{16}

You're done!

g=\frac{23}{16}

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Answer: The measurement of angle B is 34. The measurement of angle C is 108. The measurement of angle F is 72.

Step-by-step explanation:

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3 years ago
Help me<br> On this pleaseee
Evgen [1.6K]
2 rectangle shaped
1) Length = 160 mi ; Width = 40 mi
2) Length = 440 mi - 160 mi ; Width = 240 mi - 70 mi

1 triangle shape
1) base = 70 mi ; height = 440 mi - 160 mi

Area Rectangle 1 = 160 mi * 40 mi = 6,400 mi²
Area Rectangle 2 = 280 mi * 170 mi = 47,600 mi²
Area Triangle 1 = ((440 mi - 160 mi) * 70mi)/2 = (280mi * 70mi)/2 = 9,800 mi²

Total Area = 6,400 mi² + 47,600 mi² + 9,800 mi² = <span>63,800 mi²</span>
4 0
3 years ago
Find the hypotenuse of each isosceles right triangle when the legs are of the given measure. 6 sqrt 2
Gemiola [76]
Isosceles right triangles have two equal sides (a and b) that are not the hypotenuse (c). And when two sides are equal, so are their opposite angles. There are only 180° degrees in any triangles, thus the right angle = 90°, so 90 left for the two equal, means that 2x=90,
x = 45°.

There are several ways to go about solving a triangle like this. The best and easiest is simply to memorize that the hypotenuse is exactly root2 times the other sides. Or, each isosceles side is the hypotenuse (c) ÷ root2
a = b = c \div  \sqrt{2} \\ c  = a\sqrt{2}  \\ c = 6 \sqrt{2} \times \sqrt{2}  = 6 \times 2 = 12
Another way to do it is the longer proof of Pythagorean Theorem:
{c}^{2}  =  {a}^{2}  +  {b}^{2}... \:  \:  c =   \sqrt{({a}^{2}  +  {b}^{2})}  \\
c= \sqrt{({6 \sqrt{2}) }^{2} + ({6 \sqrt{2})}^{2}}  \\ =  \sqrt{(2 \times{(6 \sqrt{2} )}^{2} )}  =  \sqrt{2(36 \times 2)}  \\ c =  \sqrt{144}  = 12

7 0
3 years ago
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slega [8]

Answer:

A

Step-by-step explanation:

If the number of people in the theater must be under 240, then there must be less than 10 seats in each row on the floor to meet fire safety regulations.

if X=10 then, 15 times 10 plus 90 = 240.

Since the number of people must be under 240, there must be less than 10 seats in each row on the floor.

6 0
2 years ago
If a = 38 ft, b = 15 ft, c = 19 ft, and d = 19 ft, what is the area of the living room and hallway together?
Anvisha [2.4K]

Answer:

The area of the living room and hallway together = 437ft²

Question:

The complete question related to the one above found at 'Geometry in class' is stated below:

Abbey is getting new carpet in her living room and hallway.

The following diagram shows the two together.

If = 38 ft, b = 15 ft, c = 19 ft, and d = 19 ft, what is the area of the living room and hallway together?

Find attached the diagram of the question.

Step-by-step explanation:

To determine the area of the living room and hallway together, we would break the diagram into two rectangles.

Calculate the area of each and sum the two outcomes together.

Find attached the diagrams of the solution.

Given: a = 38 ft, b = 15 ft, c = 19 ft, and d = 19 ft,

Area of rectangle = length × breadth

Area of rectangle 1 = a × (d-b)

= 38 × (19-15) = 38× 4

Area of rectangle 1 = 152ft²

Area of rectangle 2 = c × b

= 19 × 15 = 285

Area of rectangle 2 = 285ft²

The area of the living room and hallway together = Area of rectangle 1 + Area of rectangle 2

= 152ft² + 285ft²

The area of the living room and hallway together = 437ft²

5 0
3 years ago
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