The volume of the pyramid would be 2406.16 cubic cm.
<h3>How to find the volume of a square-based right pyramid?</h3>
Supposing that:
The length of the sides of the square base of the pyramid has = b units
The height of the considered square-based pyramid = h units,
The pyramid below has a square base.
h = 24.4 cm
b = 17.2 cm
Then, its volume is given by:
Therefore, the volume of the pyramid would be 2406.16 cubic cm.
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The answer is the second option which is : - 29
Answer:
Step-by-step explanation:
Domain is all the x's and range is all the y's. There's no reason why you couldn't pop any x into the given equation and calculate it and get a number out. So literally ANY x can be used and found on this graph. So the domain is all real numbers, one of the first two answers is going to be the right one. Now, the range is all the y's on the graph. The problem says that the parabola opens down, which means it has a highest point. There is no graph above that point. That's the point (-1, 16). So 16 is the highest y-value you can find on the graph. All the rest of the y's are smaller. The range is all the y's such that the y's are 16 and smaller...in math that's written {y | y <= 16} So the second answer is the right one.
To solve for c, you need to get c onto one side of the equation, or make it c=__. So what I would do first is subtract a/b from both sides
a/b + c = d/c
-a/b
a/b - a/b + c = d/c - a/b
c = d/c-a/b