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tia_tia [17]
3 years ago
10

The electron-domain geometry of a carbon-centered compound ch4 is tetrahedral. the hybridization of the central carbon atom is _

_______.
Chemistry
1 answer:
Nata [24]3 years ago
5 0
The  hybridization  of  the   central  carbon  compound  CH4  tetrahedral  is
SP^3 hybridization 

In   tetrahedral  molecular  geometry    a central atom  is  located  at the  center  with  4  substituent  that  are located at  the  corners  of  tetrahedron. Example  in methane  molecules  is made  up of  b equally  spaced sp^3  hybrid  orbital  forming  bond  angle  of   109.5
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stealth61 [152]
English please i cant understand
8 0
3 years ago
Explain why 5.00 grams of salt does not contain the same number of particles as 5.0 grams of sugar​
Tom [10]

Answer:

5.00 grams of salt contain more particles than 5.0 grams of sugar​

Explanation:

Salt = NaCl

Molar mass = 58.45  g/mol

Sugar = C₁₂H₂₂O₁₁

Molar mass = 342.3 g/mol

Sugar's molar mass is higher than salt.

So 1 mol of sugar weighs more than 1 mol of salt

But 5 grams of salt occupies more mole than 5 grams of sugar

5 grams of salt = 5g / 58.45 g/m = 0.085 moles

5 grams of sugar = 5g/ 342.3 g/m = 0.014 moles

In conclusion, we have more moles of salt in 5 grams; therefore there are more particles than in 5 g of sugar.

3 0
3 years ago
In many species, a transition metal has an unusually high or low oxidation state. Write balanced equations for the following and
dedylja [7]

When `CO_(2)` is bubbled through a cold pasty solution of barium peroxide in water, `H_(2)O_(2)` is obtained. <br> `BaO+CO_(2)+H_(2)OtoBaCO_(3)+H_(2)O_(2)` Barium carbonate being insoluble is filtered off. This is known as Merck's process.

<h3>What is meant by Perhydrol?</h3>

perhydrol (countable and uncountable, plural perhydrols) A stabilised solution of hydrogen peroxide.

<h3>What is Merck's Perhydrol?</h3>

Uses: Perhydrol is used as an antiseptic for wounds, and also acts as a germicide to kill bacteria and germs.

Being a strong oxidizing agent it has bleaching properties and acts as a ripening agent.

Learn more about merck's process here:

<h3>brainly.com/question/16856280</h3><h3 /><h3>#SPJ4</h3>

7 0
2 years ago
During beta-oxidation of fatty acids, ___________ is produced in peroxisomes but not in mitochondria. A) acetyl-CoA B) FADH 2 C)
stepan [7]

Answer:

The correct option is D

Explanation:

Normally, beta-oxidation of fatty acid occurs in the mitchondrial matrix, however, when the fatty acid chains are too long, the beta-oxidation occurs in the peroxisomes <u>where the oxidation is not attached to ATP synthesis but rather transferred (i.e high energy electrons are transferred) to O₂ to form hydrogen peroxide</u> (H₂O₂). This is the major difference between the beta-oxidation that occurs in the peroxisomes to that which occurs in the mitochondria.

4 0
3 years ago
The equilibrium constant, Kc, for the following reaction is 0.967 at 650 K. 2NH3(g) N2(g) 3H2(g) When a sufficiently large sampl
AlekseyPX

Answer: Concentration of NH_3 in the equilibrium mixture is 0.31 M

Explanation:

Equilibrium concentration of H_2 = 0.729 M

The given balanced equilibrium reaction is,

                 2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)

Initial conc.            x                0           0

At eqm. conc.     (x-2y) M     (y) M   (3y) M

The expression for equilibrium constant for this reaction will be:

3y = 0.729 M

y = 0.243 M

K_c=\frac{[y]\times [3y]^3}{[x-2y]^2}

Now put all the given values in this expression, we get :

K_c=\frac{0.243\times (0.729)^3}{(x-2\times 0.243)^2}

0.967=\frac{0.243\times (0.729)^3}{(x-2\times 0.243)^2}

x=0.80

concentration of NH_3 in the equilibrium mixture = 0.80-2\times 0.243=0.31

Thus concentration of NH_3 in the equilibrium mixture is 0.31 M

3 0
3 years ago
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