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tia_tia [17]
3 years ago
10

The electron-domain geometry of a carbon-centered compound ch4 is tetrahedral. the hybridization of the central carbon atom is _

_______.
Chemistry
1 answer:
Nata [24]3 years ago
5 0
The  hybridization  of  the   central  carbon  compound  CH4  tetrahedral  is
SP^3 hybridization 

In   tetrahedral  molecular  geometry    a central atom  is  located  at the  center  with  4  substituent  that  are located at  the  corners  of  tetrahedron. Example  in methane  molecules  is made  up of  b equally  spaced sp^3  hybrid  orbital  forming  bond  angle  of   109.5
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in an experiment 3.5g of element A reacted with 4.0g of element G to form a compound Calculate the empirical formula for this co
kolezko [41]

Additional information

Relative atomic mass(Ar) : A=7, G=16

The empirical formula : A₂G

<h3>Further explanation</h3>

Given

3.5g of element A

4.0g of element G

Required

the empirical formula for this compound

Solution

The empirical formula is the smallest comparison of atoms of compound forming elements.

The empirical formula also shows the simplest mole ratio of the constituent elements of the compound

mol of element A :

\tt mol=\dfrac{mass}{Ar}\\\\mol=\dfrac{3.5}{7}=0.5

mol of element G :

\tt mol=\dfrac{4}{16}=0.25

mol ratio A : G = 0.5 : 0.25 = 2 : 1

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3 years ago
Water samples containing dissolved substances are called _____ solutions. A. solvent B. aqueous C. anhydrous D. elementary
dlinn [17]
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7 0
3 years ago
Using the word bank below label the wave.
lesya692 [45]

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Hydrogen iodide, HI, is formed in an equilibrium reaction when gaseous hydrogen and iodine gas are heated together. If 20.0 g of
Kaylis [27]

Answer: D. 19.9 g hydrogen remains.

Explanation:

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

a) moles of H_2

\text{Number of moles}=\frac{20.0g}{2g/mol}=10.0moles

b) moles of I_2

\text{Number of moles}=\frac{20.0g}{254g/mol}=0.0787moles

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According to stoichiometry :

1 mole of I_2 require 1 mole of H_2

Thus 0.0787 moles of l_2 require=\frac{1}{1}\times 0.0787=0.0787moles of H_2

Thus l_2 is the limiting reagent as it limits the formation of product and H_2 acts as the excess reagent. (10.0-0.0787)= 9.92 moles of H_2are left unreacted.

Mass of H_2=moles\times {\text {Molar mass}}=9.92moles\times 2.01g/mol=19.9g

Thus 19.9 g of H_2 remains unreacted.

5 0
3 years ago
If I have 12 protons, how many neutrons and electrons would I need to make a stable atom?
lesantik [10]

Answer:

im pretty sure you need 15 in all but dont get mad it thats wrong, so you would i think need 3 neutrons

Explanation:

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