Answer: CF4
Explanation:
Calculate the molar mass of each compound. Divide the molar mass of Carbon by the molar mass of each compound, then multiply the answer by 100 to get the percentage.
CF4= 12+(19X 4)
=12+76= 88 g/mol
%C= 12/88 x 100= 13.64%
CO2= 12+(16 X 2)
12+32= 44 G/MOL
%C= 12/44 x 100= 27.3%
CH4= 12+ (1 X4)
=12+4
=16 G/MOL
%C= 12/16 X 100= 75%
C204
(12X2) + (16X4)
24+64
= 88 g/mol
%C= 24/88 x 100
= 27.3%
Answer: 1 × 10−2 M
Explanation: Kw is known as the constant of water dissociation and its value is found to be
. It is the product of the concentration of [H3O+] and [OH -] ions .
Dissociation of water can be represented by -

Kw = [H3O+] [OH -]
As we know that pKw = - log Kw,
Thus pKw = 14
pOH = - log OH- = - log (10^{-12}) = 12
and pKw = pH + pOH
14 = pH + 12
pH = 14 - 12 = 2
pH = -log H3O+
2 = -log H3O+
Therefore, [H3O+] = 1 × 10−2 M
Answer:
( About ) 5.7 grams
Explanation:
Take a look at the attachment below for a proper explanation;
Answer:
Explanation:
Ratio of C : H : N : O in grams
= 72.15 : 7.08 : 4.68 : 16.03 in grams
Ratio of C : H : N : O in moles
72.15/12 : 7.08/1 : 4.68/14 : 16.03/16 in moles
6.01 : 7.08 : .334 : 1.00
6.01/ .334 : 7.08/.334 : .334/.334 : 1.00/.334 in moles
18 : 21.19 : 1 : 3
18 : 21 : 1 : 3
empirical formula = C₁₈H₂₁NO₃
It is codeine .
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