B. One
I believe that earth is the only planet that has life that we know of on it.
Answer: Option C is correct.
Explanation: Average kinetic energy is directly proportional to the absolute temperature. Higher the temperature means higher the kinetic energy.
Average kinetic energy is given by:
Where, k = Boltzman constant
T = Temperature
We are given different temperatures, so to compare they all should have the same units.
a) 298K
b) 267K
c) 27°C = 273+27 = 300K
d) 12°C = 273+12 = 285K
Looking at the temperature values, C part will have the highest average kinetic energy.
Answer:
There is 1.6 L of NO produced.
Explanation:
I assume you have an excess of NH3 so that O2 is the limiting reagent.
<u>Step 1:</u> Data given
2.0 liters of oxygen reacts with ammonia
<u>Step 2:</u> The balanced equation
4NH3 + 5O2 → 4NO + 6H2O
For 4 moles of NH3, we need 5 moles of O2 to produce 4 moles of NO and 6 moles of H2O
Consider all gases are kept under the same conditions for pressure and temperature, we can express this mole ratio in terms of the volumes occupied by each gas.
This means: when the reaction consumes 4 liters of ammonia (and 5 liters of oxygen) it produces 4 liters of nitrogen monoxide
Now, when there is 2.0 liters of oxygen consumed, there is 4/2.5 = 1.6 L of nitrogen monoxide produced.
There is 1.6 L of NO produced.
Answer:
B. 2g
Explanation:
So first you have to find the mole to mole ratio then convert it to grams if that makes sense. So the mole to mole ratio is 2 ammonia to 3 hydrogen gas. So then after you do that conversion you can solve for grams then. Sorry I am not that great at explaining.
Answer:
mass of oxygen gas in Kg = 15.0Kg
Explanation:
Volume of air in the room = 4.0m*5.0m*2.5m = 50m³
volume of oxygen in the room = 21/100 * 50m³ = 10.5m³
using the ideal gas equation; PV=nRT
number of moles of oxygen gas, n = PV/RT
At STP, P = 1atm, V = 10.5m³ = (10.5*1000)dm³ = 10500dm³, R = 0.082 atmdm³K⁻¹mol⁻¹, T = 273K
n = 1 * 10500/ (273 *0.082)
n = 469.04 moles
mass of oxygen gas in Kg = (no of moles * molar mass)/1000
molar mass of oxygen gas = 32g
mass of oxygen gas in Kg = (469.04 * 32)/1000
mass of oxygen gas in Kg = 15.0Kg
