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Juliette [100K]
3 years ago
5

Whats's the capital of ur mom?

Chemistry
2 answers:
enyata [817]3 years ago
8 0

Answer:

around the corner and up ur butttt

Explanation:

Dafna11 [192]3 years ago
8 0

Answer:

ur dads paycheck

Explanation:

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The moon's craters are remnants of meteorite collisions. suppose a fairly large asteroid that has a mass of 5.00×10^12 kg (about
Paul [167]

<u>Given:</u>

Mass of asteroid, M1 = 5.00*10¹² kg

Velocity of asteroid V1 = 15.0 km/s

Mass of moon, M2 = 7.36*10²² kg

<u>To determine:</u>

The recoil velocity of moon, V2

<u>Explanation:</u>

Since the collision is perfectly inelastic, momentum is conserved. therefore,

M1 * V1 = M2* V2

V2 = M1*V1/M2 =  5.00*10¹² *15.0 /7.36*10²²  = 1.02*10⁻⁹ km/s


5 0
3 years ago
Read 2 more answers
A 9.000L tank at 27.0°C is filled with 5.29g of sulfur tetrafluoride gas and 15.6g of carbon dioxide gas. You can assume both ga
Colt1911 [192]

Answer:

Mole fraction SF₄: 0,121

Mole fraction CO₂: 0,879

Partial pressure SF₄: 0,134 atm

Partial pressure CO₂: 0,968 atm

Total pressure: 1,102 atm

Explanation:

The moles of sulfur tetrafluoride gas and carbon dioxide gas are:

5,29g SF₄×\frac{1mol}{108,07g}= <em>0,0489 moles SF₄</em>

15,6 CO₂×\frac{1mol}{44,01g}= <em>0,354 moles CO₂</em>

Mole fraction SF₄:

X_{SF_{4}} = \frac{0,0489mol}{0,0489+0,354} = <em>0,121</em>

Mole fraction CO₂:

X_{CO_{2}} = \frac{0,354mol}{0,0489+0,354} = <em>0,879</em>

It is possible to obtain partial pressure of both gases with moles of each gas using:

P = nRT/V

Where n are respective moles, R is gas constant (<em>0,082atmL/molK</em>), T is teemperature (27°C=<em>300,15K</em>), V is volume (<em>9,0000L)</em>

Replacing:

Partial pressure SF₄: <em>0,134atm</em>

Partial pressure CO₂: <em>0,968atm</em>

Now, the sum of the partial pressures is the total pressure in the tank, that means:

Total pressure: 0,134atm + 0,968atm = <em>1,102atm</em>

<em></em>

I hope it helps!

6 0
3 years ago
NEED HELP ASAP PLEASE
Lostsunrise [7]

Answer:

here hope it helps

Explanation:

covalent bonds

5 0
3 years ago
Read 2 more answers
Determine the freezing point of a solution which contains 0.31 mol of sucrose in 175 g of water. kf = 1.86ï°c/m
barxatty [35]
Freezing point depression is a colligative property.

The formula that rules it is:

ΔT f = Kf * m

Where m is the molality of the solution => m = moles of solute / Kg of solvent

=> m = 0.31 mol / 0.175 kg = 1.771 m

And kf = 1.86 °C/m

=> ΔTf = 1.771 m * 1.86 °C / m = 3.3 °C

 => Freezing point of the solution = normal freezing point of water - 3.3 °C = 0 - 3.3°C = - 3.3°C.

Answer: -3.3 °C


8 0
4 years ago
Ralph's friend invited him to attend a hard rock concert. Ralph did not want to go because he assumed other people who attended
Iteru [2.4K]

Answer:

Prejudice

Explanation:

8 0
3 years ago
Read 2 more answers
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