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WARRIOR [948]
3 years ago
7

A student tests a solid sample of a compound and determines that it does not conduct electric

Chemistry
1 answer:
Vitek1552 [10]3 years ago
7 0

Answer:

A

Explanation:

because they are non polar so would not conduct electricity :)

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Write the net ionic equation for this precipitation reaction. Include physical states. ( NH 4 ) 2 CO 3 ( aq ) + Ca ( ClO 4 ) 2 (
Bad White [126]

Answer:

The net ionic equation:

Ca^{2+}(aq)+CO_{3}^{2-}(aq) \rightarrow CaCO_{3}(s)

Explanation:

The given chemical reaction is as follows.

(NH_{4})_{2}CO_{3}(aq)+Ca(ClO_{4})_{2}(aq) \rightarrow CaCO_{3}(s)+2NH_{4}ClO_{4}(aq)

The total ionic equation is as follows.

2NH_{4}^{+}(aq)+ CO_{3}^{2-}(aq)+Ca^{2+}(aq)+2ClO_{4}^{-}(aq) \rightarrow CaCO_{3}(s)+2NH_{4}^{+}(aq)+2ClO_{4}^{-}

Similar ions on the both sides of the reaction will be cancelled.

The remaining reaction is

Ca^{2+}(aq)+CO_{3}^{2-}(aq) \rightarrow CaCO_{3}(s)

Therefore, the net ionic reaction is as follows.

Ca^{2+}(aq)+CO_{3}^{2-}(aq) \rightarrow CaCO_{3}(s)

8 0
4 years ago
How many grams of NaCI are present in 11.00 moles
Amiraneli [1.4K]

Answer: 642.93 g of NaCl

Explanation:

11.00 mol NaCl  x  __58.448 g__  =  642.928 g of NaCl

                                 1 mol NaCl

I would round to 642.93 g of NaCl, but round to however many significant figures asked for.

My chemistry teacher made this map (image attached) to teach us how to do conversions. Just follow the map. I think it's pretty straight forward. I hope this helps.

7 0
3 years ago
Which of the following is an example of physical weathering?   Frost wedging  Acid rain  Oxidation  Carbonic acid
bearhunter [10]
I would say Frost Wedging because water must move, a physical act, and then in must freeze, also a physical act, and then the act of it freezing causes cracks known as frost wedging and that is definitely a physical act. Hope that helps!
4 0
4 years ago
Read 2 more answers
A solution is made containing 4.92 g of sodium lithium chloride per 347 g of water.
Margaret [11]

% mass of a solution is the mass of the solute present per 100 g of solution. It can be calculated using the formula,

Mass % = \frac{Mass of solute (g)}{Mass of solution (g)} * 100

Mass of solute = 4.92 g

Mass of solvent, water = 347 g

Total mass of solution = 347 g + 4.92 g = 351.92 g

Mass % of the solute = \frac{4.92 g}{351.92 g} * 100 = 1.398 %

Therefore, the weight/weight % = 1.398 %

7 0
3 years ago
Why is it important for a scientist studying greenhouse effect to know about mater,forces and energy
vova2212 [387]
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8 0
4 years ago
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