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geniusboy [140]

2 years ago

7

this is a pretest so i haven't learned about any of this yet please provide help i thought it was the cross multiplication thing

but its not

1 answer:

Kipish [7]2 years ago

4 0

This triangle has height 8 and base 4, so it's area is 4*8/2=16.

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Vincent started the year with $179 in his account at the health spa. Each time he uses the spa, $15 is taken out of the account.

wlad13 [49]

Answer:

Vincent would be able to use the spa 9 more times.

Step-by-step explanation:

$135 divided by $15 = 9

4 0

2 years ago

4. To be linear means to have a constant (the same)

viva [34]

It post to be 2.x4=x1

3 0

2 years ago

Need help plz I’m almost done

JulsSmile [24]

Hello!

The graph, (2/5)^x is an exponential function.

Since there is not a negative symbol in the front of the function, options A and B are incorrect.

For option 3 to be correct, there would need to be a negative symbol in front of the exponent, x.

So therefore, the answer option 4. (Also, I'll post a graph. :))

8 0

2 years ago

The width of a rectangle is 2x + 4 and the length of the

iren [92.7K]

Given:

Width of a rectangle = $2x+4$

Length of the rectangle = $6x+12$

To find:

The ratio of the width to the length.

Solution:

We need to find the ratio of the width to the length.

$\text{Required Ratio}=\dfrac{\text{Width}}{\text{Length}}$

Putting the given values, we get

$\text{Required Ratio}=\dfrac{2x+4}{6x+12}$

$\text{Required Ratio}=\dfrac{2(x+2)}{6(x+2)}$

$\text{Required Ratio}=\dfrac{2}{6}$

$\text{Required Ratio}=\dfrac{1}{3}$

$\text{Required Ratio}=1:3$

Therefore, the ratio of the width to the length is 1:3.

8 0

2 years ago

Find x and y please

Alexandra [31]

Answer:

Answer:

x → 4.24
y → 4.24

Step-by-step explanation:

» x and y can only be got through using trigonometric ratios:

✍ <u> </u><u>For</u><u> </u><u>x</u><u> </u>:

${ \tt{ \sin( \theta) = \frac{opposite}{hypotenuse} }} \\ \\ { \tt{ \sin(45 \degree) = \frac{x}{6} }} \\ \\ { \tt{x = 6 \times \sin(45 \degree) }} \\ { \tt{x = 4.24}}$

✍ <u> </u><u>F</u><u>o</u><u>r</u><u> </u><u>y</u><u> </u>:

${ \tt{ \cos( \theta) = \frac{adjacent}{hypotenuse} }} \\ \\ { \tt{ \cos( 45 \degree) = \frac{y}{6} }} \\ \\ { \tt{y = 6 \times \cos(45 \degree) }} \\ { \tt{y = 4.24}}$

6 0

2 years ago

Read 2 more answers