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geniusboy [140]
3 years ago
7

this is a pretest so i haven't learned about any of this yet please provide help i thought it was the cross multiplication thing

but its not

Mathematics
1 answer:
Kipish [7]3 years ago
4 0
This triangle has height 8 and base 4, so it's area is 4*8/2=16.
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Factor 15x3-5x+6x-2 by grouping. What is the resulting expression?
cricket20 [7]

Answer: (5x2 + 2)(3x – 1)

Step-by-step explanation:

8 0
4 years ago
Find and correct the error of the following factor.
pshichka [43]

3x² + xy2 – 3xy-y? >> 3x² - xy - y

line 1: = (3x² + xy2)+(-3xy – y?)

ANS 3x² - xy - y 《Correct》

line 2: = x(3x + y2) - y(3x – y2)

ANS 3x² - xy +2y²

line 3: = (x-y) (3x +y?)

ANS 3x² - 2xy - y²

If it incorrect, I'm sorry.

3 0
4 years ago
Does -3(x-4)= -3x=12 have one solution, many solutions, or no solutions at all?
TEA [102]

Answer:

If the expression is:

-3x + 12 = -3x + 12, infinite solutions

If the expression is:

-3x + 12 = -3x - 12, no solutions

Step-by-step explanation:

Step 1: Distribute

-3x + 12 = 3x = 12

If both lines have the same slope and same y-int, they are the same line and therefore have infinite solutions.

If both lines have the same slope but different y-int, then they are parallel and therefore have no solutions.

4 0
3 years ago
Need help plz help me pls
Orlov [11]
The answer u are looking for is 30
8 0
4 years ago
Read 2 more answers
Find the center and radius of the circle with the equation: a. center: (-5, 1) radius: 4 c. center: (-5, 1) radius: 2 b. center:
damaskus [11]

Answer:

Step-by-step explanation:

if center= (h,k)

radius=r

eq. of circle is (x-h)^2+(y-k)^2=r^2

a.

center= (-5,1)

radius=4

eq. of circle is (x+5)^2+(y-1)^2=4^2

b.

center=(5,-1)

radius=4

eq. of circle is  (x-5)^2+(y+1)^2=4^2

c.

center=(-5,1)

radius=2

eq. of circle is (x+5)^2+(y-1)^2=2^2

d.

center=(5,-1)

radius=2

eq. of circle is (x-5)^2+(y+1)^2=2^2

4 0
4 years ago
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