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Option C
The distance of a spin of one full rotation is 31.4 feet
<em><u>Solution:</u></em>
Given that,
A circular merry-go-round has a radius of 5 feet
Radius = 5 feet
We have to find the distance of spin for one full rotation
Distance covered in 1 full of rotation is equal to circumference of circle
<em><u>The circumference of circle is given as:</u></em>
Where "r" is the radius
Thus the distance of a spin of one full rotation is 31.4 feet
Using relations in a right triangle, it is found that the length of AC is of 14 cm.
<h3>What are the relations in a right triangle?</h3>The relations in a right triangle are given as follows:
- The sine of an angle is given by the length of the opposite side to the angle divided by the length of the hypotenuse.
- The cosine of an angle is given by the length of the adjacent side to the angle divided by the length of the hypotenuse.
- The tangent of an angle is given by the length of the opposite side to the angle divided by the length of the adjacent side to the angle.
Researching this problem on the internet, we have that:
- The opposite leg to angle A is of 48 cm.
- sin(A) = 0.96.
Hence the hypotenuse is found as follows:
sin(A) = 48/h
0.96 = 48/h
h = 48/0.96
h = 50 cm.
The length of side AC is the other leg of the triangle, found using the Pythagorean Theorem, hence:
x = 14 cm.
More can be learned about relations in a right triangle at brainly.com/question/26396675
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