Answer:
That's all I could think that you might need. Finish your question please
Step-by-step explanation:
Together: 13
Andre has 3 more
The length and width of a new rectangle playing field are 214 yards and 52 yards respectively.
<h3>What is the area of the rectangle?</h3>
It is defined as the area occupied by the rectangle in two-dimensional planner geometry.
The area of a rectangle can be calculated using the following formula:
Rectangle area = length x width
We have:
The length of a new rectangle playing field is 6 yards longer than quadruple the width.
Let's suppose the length is l and width is w of a rectangle:
From the problem:
l = 6 + 4w
Perimeter P = 2(l + w)
532 = 2(l + w)
Plug l = 6+4w in the above equation:
532 = 2(6 + 4w + w)
266 = 6 + 5w
260 = 5w
w = 52 yards
l = 6 +4(52) = 214 yards
Thus, the length and width of a new rectangle playing field are 214 yards and 52 yards respectively.
Learn more about the area of rectangle here:
brainly.com/question/15019502
#SPJ1
Answer:
6ab(2a-3b-5b²)
Step-by-step explanation:
6(2a²b-3ab²-5ab³)
6a(2ab-3b²-5b³)
6ab(2a-3b-5b²)
Let x = hours to meet
train one has a 2 hour head start or 210 km head start
210 + 105x = 135x
30x = 210
x = 7 hours to meet
15444 ways we can choose 5 objects, without replacement, from 15 distinct objects.
Given that, suppose we want to choose 5 objects, without replacement, from 15 distinct objects.
<h3>What is a permutation?</h3>
A permutation is a mathematical calculation of the number of ways a particular set can be arranged, where the order of the arrangement matters.
Now,
= 13!/(13-5)!
= 13!/8! = 13x12x11x10x9= 1287 x 120 = 15,444
Therefore, 15444 ways we can choose 5 objects, without replacement, from 15 distinct objects.
To learn more about the permutation visit:
brainly.com/question/1216161.
#SPJ1