Answer: The concentration of excess in solution is 0.017 M.
Explanation:
1.
moles of
1 mole of give = 1 mole of
Thus 0.019 moles of give = 0.019 mole of
2. moles of
According to stoichiometry:
1 mole of gives = 2 moles of
Thus 0.012 moles of give = moles of
As 1 mole of neutralize 1 mole of
0.019 mole of will neutralize 0.019 mole of
Thus (0.024-0.019)= 0.005 moles of will be left.
Thus molarity of in solution is 0.017 M.
<span>Erosion causes things to move into new places
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The diagram is a simple circuit of a battery connected to a light bulb in a circuit with a switch.
The corresponding names, starting with the battery and going counterclockwise, are:
1) Battery
2) Wire
3) socket
4) switch
Answer:
10.7 g of KOH
Explanation:
First of all, we determine the reaction:
2K (s) + 2H₂O(l) → H₂(g) + 2KOH(aq)
We convert the mass of K, to moles → 7.5 g . mol/39.1 g = 0.192 moles
Ratio is 2:2, so the moles I have of K must produce the same moles of KOH. In this case, the produces moles of KOH are 0.192 moles.
We convert the moles to mass, to finish the answer:
0.192 mol . 56.1g /1mol = 10.7 g of KOH