True or false: potential energy increases as like charges get closer to one another

sattari [20]

Remember that enzymes always accelerate chemical equations, depending on what the enzyme is consisted of. As the enzymes are burned the reaction or amount of chemical reactions decreases.

4 0

3 years ago

Describe the redox reaction. Check all that apply 2AI(s) + 3ZnCI2(g) → 3Zn(s) + 2AICI3(aq).

Inga [223]

Answer:

Zinc is reduced.

The oxidation number of chlorine does not change.

Aluminum is oxidized.

Explanation:

For the reaction:

2AI(s) + 3ZnCI₂(g) → 3Zn(s) + 2AICI₃(aq).

For the elements in the reactants side:

Al has (0) oxidation state and converted to (+3) oxidation state in the products (AlCl₃), which means Al is oxidized and it is the reducing agent.

So, we can check that: Aluminum is oxidized.

Zn has the oxidation state (+2) in the reactants side (ZnCl₂) and converted to (0) in the products side (Zn), which means that Zn is reduced and it is the oxidizing agent.

So, we can check that: Zinc is reduced.

and can not check: Zinc is the reducing agent.

The oxidation state of Cl does not change, it is the same in both sides (-1).

So, we can check: The oxidation number of chlorine does not change.

and can not check: Aluminum atoms transfer electrons to chlorine atoms.

So, the choices will be:

Zinc is reduced.

The oxidation number of chlorine does not change.

Aluminum is oxidized.

4 0

4 years ago

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Substances A and B are combined. When combined, substance A, which is a black solid, sinks to the bottom of substance B which is

Makovka662 [10]

Answer:

c thats just what i do

Explanation:

4 0

3 years ago

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What is the empirical formula for a substance that contains 3.730% hydrogen, 44.44% carbon, and 51.83% nitrogen by mass?\?

Vlada [557]

Given data:

Hydrogen (H) = 3.730 % by mass

Carbon (C) = 44.44%

Nitrogen (N) = 51.83 %

This means that if the sample weighs 100 g then:

Mass of H = 3.730 g

Mass of C = 44.44 g

Mass of N = 51.83 g

Now, calculate the # moles of each element:

# moles of H = 3.730 g/ 1 g.mole-1 = 3.730 moles

# moles of C = 44.44/12 = 3.703 moles

# moles of N = 51.83/14 = 3.702 moles

Divide by the lowest # moles:

H = 3.730/3.702 = 1

C = 3.703/3.702 = 1

N = 3.702/3.702 = 1

Empirical Formula = HCN

3 0

3 years ago

Based on the thermodynamic properties provided for water, determine the energy change when the temperature of 0.750 kg of water

Vlad [161]

The energy change when the temperature of 0.750 kg of water decreased from 123 °C to 23.0 °C is -313.5 kJ.

In this problem, we are dealing with specific heat which is referred to as the sum of heat per unit mass required to raise the temperature by one degree Celsius.Since we know the boiling point of water is 100°C, at 123°C, the water is steam.

The formula we are referring to for calculating the heat energy Q

Q= m C ΔT

where m is the mass of water which is equal to 0.750 Kg, then

C is the specific heat of water equal to 4180 J/Kg °C and

ΔT is the change in temperature which is (23-123)= -100°C

So, assembling those desired values on the formula we get,

Q= 0.750 (4180) (-100)

Q=-313500

= -313.5 kJ

To know more about specific heat refer to the link brainly.com/question/13163208?referrer=searchResults.

#SPJ1

3 0

2 years ago