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AURORKA [14]
3 years ago
11

2. 7.5 g of potassium react with water to produce potassium hydroxide and hydrogen gas. Calculate the mass of potassium hydroxid

e produced. (8 points)
Chemistry
1 answer:
luda_lava [24]3 years ago
8 0

Answer:

10.7 g of KOH

Explanation:

First of all, we determine the reaction:

2K (s) + 2H₂O(l) → H₂(g) + 2KOH(aq)

We convert the mass of K, to moles → 7.5 g . mol/39.1 g = 0.192 moles

Ratio is 2:2, so the moles I have of K must produce the same moles of KOH. In this case, the produces moles of KOH are 0.192 moles.

We convert the moles to mass, to finish the answer:

0.192 mol . 56.1g /1mol = 10.7 g of KOH

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What has a higher lattice energy? MgS or BaF2
irinina [24]

Answer:

The lattice energy of MgS is 4 times larger than that of NaCl

Explanation:

because, MgS has a higher charge that is Mg2+,S2− M g 2 + , S 2 − than NaCl (Na+,Cl−) ( N a + , C l − ) .

3 0
2 years ago
A 100-w light bulb is about 16% efficient. how many joules of heat energy are siddipated by the bulb each second
pickupchik [31]

Answer:

84 Joules are wasted per second.

Explanation:

An efficiency of 16% means 84% is wasted as heat energy.  

Therefore;

For a 100W bulb;

Heat wasted = 84/100 × 100 W

                      = 84 W

Therefore;

84 W or 84 joules are wasted as heat per second

3 0
3 years ago
The reaction between A2 (two large red spheres) and B2 (two small blue spheres) to produce AB is shown in the diagram. The react
drek231 [11]

Answer:

B₂

Explanation:

The limiting reactant is always a reactant. You can determine which reactant is limiting by identifying which has the smaller mole-to-mole ratio with the product. This ratio can be found via the coefficients of the balanced reaction.

4 A₂ + 3 B₂ ---> 6 AB

4 moles A₂
------------------  = mole-to-mole ratio A₂/AB
6 moles AB

3 moles B₂
------------------  =  mole-to-mole ratio B₂/AB
6 moles AB

Since the mole-to-mole ratio between B₂ and AB is smaller, B₂ must be the limiting reactant.
                           

3 0
2 years ago
To convert from mass of A to moles of B in a stoichiometry problem, the following steps are followed:
taurus [48]

Answer:

b. mass A → moles A → moles B

Explanation:

hope this helps

4 0
3 years ago
Identify the limiting reactant when 32. 0 g hydrogen is allowed to react with 16. 0 g oxygen
Mkey [24]

Answer:

Oxygen is limiting reactant

Explanation:

2 H2  +   O2  ======> 2 H2 O

from this equation (and periodic table) you can see that

  4 gm of H combine with 32 gm O2  

     H / O  =  4/32 = 1/8

       32 /16    =  2/1    shows O is limiter

         for 32 gm H you will need 256 gm O   and you only have 16 gm

3 0
2 years ago
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