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Leto [7]
3 years ago
5

What is the solution set to the inequality 5(x - 2)(x + 4) > 0?

Mathematics
1 answer:
MaRussiya [10]3 years ago
7 0

Answer:

you can ask a tutor they will most likely to help you more

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Please check my work for this ONE QUESTION
natali 33 [55]
I think the answer is correctly answered
6 0
3 years ago
Suppose that X is a subset of Y. Let p be the proposition ‘x is an element ofX’ and let q be the proposition ‘x is an element of
Genrish500 [490]

Answer:

See answer below

Step-by-step explanation:

The statement ‘x is an element of Y \X’ means, by definition of set difference, that "x is and element of Y and x is not an element of X", WIth the propositions given, we can rewrite this as "p∧¬q". Let us prove the identities given using the definitions of intersection, union, difference and complement. We will prove them by showing that the sets in both sides of the equation have the same elements.

i) x∈AnB  if and only (if and only if means that both implications hold) x∈A and x∈B if and only if x∈A and x∉B^c (because B^c is the set of all elements that do not belong to X) if and only if x∈A\B^c. Then, if x∈AnB  then x∈A\B^c, and if x∈A\B^c then x∈AnB. Thus both sets are equal.

ii) (I will abbreviate "if and only if" as "iff")

x∈A∪(B\A) iff x∈A or x∈B\A iff x∈A or x∈B and x∉A iff x∈A or x∈B (this is because if x∈B and x∈A then x∈A, so no elements are lost when we forget about the condition x∉A) iff x∈A∪B.

iii) x∈A\(B U C) iff x∈A and x∉B∪C iff x∈A and x∉B and x∉C (if x∈B or x∈C then x∈B∪C thus we cannot have any of those two options). iff x∈A and x∉B and x∈A and x∉C iff x∈(A\B) and x∈(A\B) iff x∈ (A\B) n (A\C).

iv) x∈A\(B ∩ C) iff x∈A and x∉B∩C iff x∈A and x∉B or x∉C (if x∈B and x∈C then x∈B∩C thus one of these two must be false) iff x∈A and x∉B or x∈A and x∉C iff x∈(A\B) or x∈(A\B) iff x∈ (A\B) ∪ (A\C).

8 0
3 years ago
The point slope form of the eqaution of the line that passes through (-5,-1) and (10, -7) is y+7= -2/5 (x - 10) what is the stan
stira [4]

Answer:

<h2>2x + 5y = -15</h2>

Step-by-step explanation:

The standard form of an equation of a line:

Ax+By=C

We have the equation in point-slope form:

y+7=-\dfrac{2}{5}(x-10)

Convert it to the standard form:

y+7=-\dfrac{2}{5}(x-10)     <em>multiply both sides by 5</em>

5y+35=-2(x-10)         <em>use the distributive property </em><em>a(b + c) = ab + ac</em>

5y+35=(-2)(x)+(-2)(-10)

5y+35=-2x+20          <em>subtract 35 from both sides</em>

5y=-2x-15            <em>add 2x to both sides</em>

2x+5y=-15

7 0
3 years ago
Select the sets that are not functions.
Temka [501]
D and E are the ones that aren’t functions because they use the x-values more then once
5 0
3 years ago
Azmyne decided to spend 6 1/2 hours studying over the weekend. She spent 1 1/4 hours studying on Friday evening and 2 2/3 hours
nata0808 [166]

Answer: 2\ \dfrac{7}{12}\ \text{hours}

Step-by-step explanation:

Given

Azmyne decided to study a total of 6\ \frac{1}{2}\ hours

She spent 1\ \frac{1}{4}\ hours on Friday and  2\ \frac{2}{3}\ hours on Saturday

Hours spent on Friday

\Rightarrow 1\ \frac{1}{4}=\frac{5}{4}\ hours

Hours spent on Saturday

\Rightarrow 2\ \frac{2}{3}=\frac{8}{3}\ hours

She must study for

\Rightarrow \dfrac{13}{2}-\dfrac{5}{4}-\dfrac{8}{3}\\\\\Rightarrow \dfrac{13\times6-5\times3-8\times4}{12}=\dfrac{78-15-32}{12}\\\\\Rightarrow \dfrac{31}{12}=2\ \frac{7}{12}\ \text{hours}

4 0
3 years ago
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