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3 years ago

Which ordered pair (x, y) is a solution to the given system of linear equations? 3x+3y=-3

Mathematics

2 answers:

Andreyy893 years ago

4 0

I believe the ordered pair would be (-1,0). Hope this helps!

atroni [7]3 years ago

3 0

Answer:

(-1,0)

Step-by-step explanation:

The given system of equations is

$3x+3y=-3........(1)\\\\-2x+y=2.......(2)$

We can find the ordered pair by solving the two equations for x and y. For this we can use the elimination method.

Multiply equation (2) by -3 and add with equation (1)

$3x+3y+6x-3y=-3-6\\\\9x=-9\\\\x=-1$

Substituting the value of x in equation (1), we get

$3x+3y=-3\\\\3(-1)+3y=-3\\\\-3y=0\\\\y=0$

Thus, the solution of the system of equations is (-1,0)

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Ratios are proportional if both serve the identical tie. A method to detect if a pair of ratios remain equivalent is to rewrite them being fractions, then decrease them. If the decreased fractions are equal, the ratios are comparative.

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Read 2 more answers

scoundrel [369]

For the first point, remember this simple rule: every exponential function $a^x$ always returns $a$ when evaluated at $x = 1$ . In fact, $a^1=a$ for every possible base $a$ .

So, we can see that the graph of the exponential passes through the point $(1,y)$ where $y$ appears to be between 1 and 2. So, the only feasible option would be $y = 1.8^x$ , because it passes throught the point $(1,1.8)$ because $f(1) = 1.8^1 = 1.8$ .

The other functions are wrong because:

$0.45^x$ would pass through $(1,0.45)$ , which would be between 0 and 1 on the y axis
$2.4^x$ would pass through $(1,2.4)$ , which would be between 2 and 3 on the y axis
$0.31^x$ would pass through $(1,0.31)$ , which would be between 0 and 1 on the y axis

As for the second question, you simply have to plug in the values: the function

$f(x) = 7^x$

means that you have to choose an input, x, and use it as exponent for 7. So, if you choose x=2, it means that you have to give exponent 2 to 7, i.e. you replace the x with the specific value, 2.

So, the expression becomes

$f(2) = 7^2 = 49$