3 years ago

A box contains 12 cereal bars. The empty box weighs

Mathematics

1 answer:

Vesna [10]3 years ago

4 0

Answer:

1.4oz

Step-by-step explanation:

You subtract the weight of the box and the bars with the empty box. Then divide the answer you got from that, with 12 and you get your answer.

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For a normal distribution with μ=500 and σ=100, what is the minimum score necessary to be in the top 60% of the distribution?

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Answer:

475.

Step-by-step explanation:

We have been given that for a normal distribution with μ=500 and σ=100. We are asked to find the minimum score that is necessary to be in the top 60% of the distribution.

We will use z-score formula and normal distribution table to solve our given problem.

$z=\frac{x-\mu}{\sigma}$

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Let us find z-score corresponding to normal score to 40% or 0.40.

Using normal distribution table, we got a z-score of $-0.25$ .

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$-0.25*100=\frac{x-500}{100}*100$

$-25=x-500$

$-25+500=x-500+500$

$x=475$

Therefore, the minimum score necessary to be in the top 60% of the distribution is 475.

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Yoko is trying to save money for a new bicycle. She sets up a budget as shown below. Yoko’s Monthly Budget Description Income Po

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