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Alex
2 years ago
9

A man observes the top of a tower of 80√3m height from 240m far from the foot of the tower, find the angle of elevation.

Mathematics
1 answer:
elena-14-01-66 [18.8K]2 years ago
7 0

Answer:

30°

Step-by-step explanation:

height \: of \: the \: tower  \: (h)\:  = 80 \sqrt{3}  \: m \\ distance \: of \: the \: observer \: (d) = 240 \: m \\  \\ let \:  \theta \: be \: the \: angle \: of \: elevation \\  \\  \therefore \: tan \theta =  \frac{h}{d}  \\ \\   =  \frac{80 \sqrt{3} }{240}  \\  \\  =  \frac{ \sqrt{3} }{3}  \\  \\  \therefore \: tan \theta =  \frac{1}{ \sqrt{3} }  \\  \\  \implies \:   tan \theta =  \tan \: 30 \degree \\  \\ \huge{ \red  {\therefore \:  \theta \:  = 30 \degree}}

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What is 4log1/2^w(2log1/2^u-3log1/2^v written as a single logarithm?
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Given:

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