A^2+b^2= 15^2
b=a-3
Use substitution
a^2+(a-3)^2= 225
a^2+a^2-6a+9=225
2a^2-6a=-216
2a^2-6a+216=0
2(a^2-3a+108)
2(a-12)(a+9)
(a-12)=0
a=12
(a+9)=0
a=-9
A is -9 or 12, but since an object can't have a negative length or width, a must be 12.
Plug this value of a in.
b=(12)-3
b=9
Final answer: Length=9, width=12
F=60, s=60/2=30
(60-x)/(30-x)=4
60-x=120-4x
60+3x=120
3x=60
x=20
s=30-x
s=30-20
s=10
So the boy was 10 years old when his father was four times his age.
Answer:
1). no
2). no
Part 2
A) (3,-2)
B) (1,0),(-3,4)
C) (4,0)
D) (3,2)
Step-by-step explanation:
<span>No because a negative times a negative will be positive and it will not equal a negative number. the square root cannot be one negative and one positive because that is against the definition of a square root.
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