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asambeis [7]
3 years ago
8

Find the exact (leave pi) and the approximate ( pi = 3.14 ) circumference for each circle

Mathematics
1 answer:
sineoko [7]3 years ago
6 0

Answer/Step-by-step explanation:

a. Circumference (C) = πd

d = 12 cm

π = 3.14

Exact value of C = π*12 = 12π cm

Approximate value of C = 12*3.14 = 37.68 cm

b. Circumference (C) = πd

d = 8 m

π = 3.14

Exact value of C = π*8 = 8π m

Approximate value of C = 8*3.14 = 25.12 m

c. Circumference (C) = πd

d = 6 km

π = 3.14

Exact value of C = π*6 = 6π km

Approximate value of C = 6*3.14 = 18.84 km

d. Circumference = πd

d = 9 ft

π = 22/7

Exact value of C = π*9 = 9π ft

Approximate value of C = 9*22/7 = 28.2857143 ≈ 28.29 ft (nearest hundredth)

e. Circumference = 2πr

r = 4 mm

π = 22/7

Exact value of C = 2*π*4 = 8π mm

Approximate value of C = 2*22/7*4 = 25.1428571 ≈ 25.14 mm (nearest hundredth)

f. Circumference = 2πr

r = 7 mi

π = 22/7

Exact value of C = 2*π*7 = 14π mi

Approximate value of C = 2*22/7*7 = 44 mi (nearest hundredth)

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Refer to attachment for marking of sides.

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<u>•</u><u> </u><u>In </u><u>∆</u><u>A</u><u>B</u><u>D</u><u> </u><u>,</u><u> </u><u>we </u><u>have</u><u> </u><u>;</u>

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\rule{200}2

<u>•</u><u> </u><u>Again</u><u> </u><u>in </u><u>∆</u><u>A</u><u>D</u><u>C</u><u> </u><u>,</u><u> </u><u>we </u><u>have</u><u> </u><u>;</u>

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\rule{200}2

<u>Again</u><u> </u><u>in </u><u>∆</u><u>A</u><u>B</u><u>C</u><u> </u><u>,</u><u> </u><u>we </u><u>have</u><u> </u><u>,</u>

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