35? I’m not sure what the question is asking
The 5 people can seat in a row in 5! ways
But we need to exclude the ways <span>that ann and bob are seated next to each other which is = 4! * 2!
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So, the number of <span>ways can ann, bob, chuck, don and ed be seated in a row such that ann and bob are not seated next to each other = 5! - 4! * 2! = 72
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<span>Another solution:
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<span>If ann seated in one of the ends, the number of ways = 3*2
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<span>If ann didn't seat in one of the ends , the number of ways = 2*3
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So, the total number of <span>ways that can <span>ann, bob be seated = 3*2 + 2*3 = 12
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The remaining persons can seat with a number of ways = 3! = 6
So, the total ways that the five persons can seat = 12*6 = 72
The probability of not picking a green is 3/4. To get this answer you would add up the blue and black marbles, giving you an answer of 9. You would then put 9 over 12, which simplified would equal 3/4. Another way to find the answer is to take 1 and subtract 1/4 because 1/4 is the probability of green marbles. Hope this helps!! Have an amazing rest of your day!! :) <span />
