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Paul [167]
3 years ago
5

A forest covers 37 comma 000 acres. A survey finds that 0.2​% of the forest is​ old-growth trees. How many acres of​ old-growth

trees are​ there?
Mathematics
1 answer:
miss Akunina [59]3 years ago
6 0

74 acres of old-growth are there in the forest

Step-by-step explanation:

To answer the question, we need to calculate the 0.2% of 37,000.We can calculate this stating that exists a linear relationship between the percentage and the number of acres. We also need to state that 37,000 acres are the 100% of the acres.

=\frac{0.2}{100} \times 37000\\ =0.002 \times 37000\\=74

We find that if 37,000 acres are the 100% of the acres ⇒ The 0.2% of the acres are 74 acres (in which there are old-growth trees).

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago
Determine the mass of a solid steel ball that has a diameter of 10 cm. The density of pure steel is 8.09 g/cm3
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Answer:

<em>The mass of the steel ball is 4,235.9 gr</em>

Step-by-step explanation:

<u>Density</u>

The density ρ of a substance is a measure of its mass per unit volume:

\displaystyle \rho=\frac{m}{V}

If the density and the volume are given, the mass can be calculated by solving the above formula for m:

m=\rho.V

We know the density of pure steel ρ=8.09 gr/cm3 and the diameter of a solid steel ball d=10 cm.

We need to calculate the volume of the sphere:

The volume of a sphere of radius r is given by:

\displaystyle V=\frac{4}{3}\cdot \pi\cdot r^3

The radius is half the diameter: r= 10/2 = 5 cm. Thus:

\displaystyle V=\frac{4}{3}\cdot \pi\cdot 5^3

Calculating:

V=523.6\ cm^3

The mass is:

m=8.09 gr/cm^3 \cdot 523.6\ cm^3

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