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taurus [48]
3 years ago
5

If y varies directly with x, and y= 10 when x = 4, find y when x = 10.​

Mathematics
1 answer:
mixer [17]3 years ago
6 0

Answer:

17

Step-by-step explanation:

bc

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Hello can you please help me posted picture of question
jarptica [38.1K]
4x^6+2x^5-2x+8+2x^8+4x+2=
2x^8+4x^6+2x^5+(4-2)x+10=
2x^8+4x^6+2x^5+2x+10

Answer: Option B: 2x^8+4x^6+2x^5+2x+10
7 0
3 years ago
Distance between (-10,9) and (-5,2)
jonny [76]

Answer:

8.60 units (3 s.f.)

Step-by-step explanation:

The distance between 2 points is given by the formula:

\sqrt{(y1 - y2)^{2} +  {(x1 - x2)}^{2}  }

Thus using the above formula,

Distance between (-10, 9) and (-5, 2)

=  \sqrt{ {(9 - 2)}^{2}  +  {( - 10 + 5)}^{2} }  \\  =  \sqrt{ {7}^{2}  + ( - 5)^{2} }  \\  =  \sqrt{74}  \\  = 8.60 \: units \: (3 \: s.f.)

8 0
3 years ago
What is Permutations and Combinations?
marissa [1.9K]

Answer:

See below

Step-by-step explanation:

Permutation is to select an object then arrange it and it cares about the orders while Combination is about only selecting an object without caring the orders.

Permutation can be expressed in math as:

\displaystyle{_n P _r = \dfrac{n!}{(n-r)!} \ \ \ (n \geq r) }

where n is a number of total object and r is a number of selected object to arrange. Hence. n cannot be less than r.

Now let's see an example of permutation, suppose we have letter A, B and C. I'd like to know how many ways these words can be arranged:

Since there are 3 letters total and 3 selected letters to arrange then:

\displaystyle{_3 P _3 = \dfrac{3!}{(3-3)!}}\\\\\displaystyle{_3 P _3 = \dfrac{3 \times 2 \times 1}{0!}}\\\\\displaystyle{_3 P _3 = \dfrac{6}{1}}\\\\\displaystyle{_3 P _3 = 6}

Therefore, there are 6 ways to arrange the letters - we can also demonstrate visually:

ABC - 1

ACB - 2

BAC - 3

BCA - 4

CAB - 5

CBA - 6

Notice that if you do visually, you'll get the same answer as the calculation of permutation!

----

Combination can be expressed mathematically as:

\displaystyle{_n C _r = \dfrac{n!}{(n-r)!r!} = \dfrac{_n P _r}{r!} \ \ \ (n \geq r) }

The difference between permutation and combination is that you only find how many ways you can select object in combination. Therefore, no arrange and doesn't care about order, just ways to select.

Suppose we have same 3 letters: A, B and C. I want to find how many ways I can select these 3 letters:

Since there are 3 letters total and 3 selected letters:

\displaystyle{_3 C _3 = \dfrac{3!}{(3-3)!3!}}\\\\\displaystyle{_3 C _3 = \dfrac{3!}{0!3!}}\\\\\displaystyle{_3 C _3 = \dfrac{3!}{3!}}\\\\\displaystyle{_3 C _3 = 1}

Hence, there is only one way to select 3 letters. This makes sense because if you have 3 letters then you can only select 3 letters only one way.

5 0
2 years ago
12,<br> Is this a discrete?
a_sh-v [17]
Yes it is a discrete
3 0
3 years ago
200z + 50 = 8000 solve this problem
kramer

Answer:

39.75

Step-by-step explanation:

First, subtract 50 from both sides

200z + 50 - 50 = 8000 - 50

200z = 7950

Then isolate the variable by dividing both sides by 200

200z/200 = 7950/200

z=39.75

8 0
2 years ago
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