Answer:
The 50th term is 288.
Step-by-step explanation:
A sequence that each term is related with the prior by a sum of a constant ratio is called a arithmetic progression, the sequence in this problem is one of those. In order to calculate the nth term of a setence like that we need to use the following formula:
an = a1 + (n-1)*r
Where an is the nth term, a1 is the first term, n is the position of the term in the sequence and r is the ratio between the numbers. In this case:
a50 = -6 + (50 - 1)*6
a50 = -6 + 49*6
a50 = -6 + 294
a50 = 288
The 50th term is 288.
Perimiter=legnth +legnth+width+width or
perimiter=2legnth+2width or
perimmiter=2(legnth+widht)
perimiter=2(10+4)
perimiter=2(14)
perimiter=28 feet
You multiply 2 1/2 (2.5) hours time 4 and you answer is 10
Hi there!
We can begin by simplifying cos(a + b) to find an equivalent expression.
With a sum of angles identity for cosine, we can determine that:
cos(a + b) = cos(a)cos(b) - sin(a)sin(b)
In this instance, we have to multiply this expression by csc(a)csc(b). Therefore:
(csc(a)csc(b)) · (cos(a)(cos(b) - sin(a)sin(b))
Distribute:
(csc(a)(csc(b))(cos(a)(cos(b)) - (csc(a)csc(b))(sin(a)sin(b))
Rewrite csc as 1/sin to simplify:
(1/sin(a) * 1/sin(b))(cos(a)(cos(b)) - (1/sin(a) * 1/sin(b))(sin(a)sin(b))
Multiply:
cos(a)/sin(a) * cos(b)/sin(b) - 1/sin(a) * sin(a) * 1/sin(b)*sin(b) <--- = 1
We now have remaining:
cos(a) / sin(a) * cos(b)/sin(b) - 1
Simplify to cotangent:
cot(a) * cot(b) - 1