Answer: D 90
Step-by-step explanation:
One way to do this follows: Find the ratio, r, which when multiplied by each of the four numbers in the ratio produces the actual number of parts present:
4r + 11r + 9r + 6r = 60
Summing these up results in 30r = 60, so r is 2.
There are 4(2), or 8, nails,
11(2), or 22, screws,
9(2), or 18, washers, and
6(2), or 12, brackets.
Note that 8 + 22 + 18 + 12 = 60 (total number of parts)
If 5 carpenters have identical boxes, there will be 5(18), or 90, total washers.
The answer to your problem is 226.08
The question given is incomplete, here is the complete one gotten from google:
A gas station stores its gasoline in a tank under the ground. The tank is a cylinder lying horizontally on its side. (In other words, the tank is not standing vertically on one of its flat ends.) If the radius of the cylinder is 2 meters, its length is 6 meters, and its top is 4 meters under the ground, find the total amount of work needed to pump the gasoline out of the tank. (The density of gasoline is 673 kilograms per cubic meter; use g=9.8m/s^2
Answer:
Work = 2,238,031 Joules
Step-by-step explanation:
Assuming the tank is initially full, and work is needed to be done to make it empty, and get the fuel to the ground level.
The tank center line is the center of gravity of the fuel, and its distance below ground level is 4+ 0.5 m m= 4.5 m.
Fuel mass = π * (2)²*6*673 = 3.142*6*673 = 50,749 Kg
Work = weight*height
= mass*acceleration due to gravity,g*height
=50,749*9.8*4.5 = 2,238,030.9
Work = 2,238,031 Joules
we are given
Firstly, we will simplify it
At x=5.5:
we can plug x=5.5
At x=5.1:
we can plug x=5.1
At x=5.05:
we can plug x=5.05
At x=5.01:
we can plug x=5.01
At x=5.005:
we can plug x=5.005
At x=5.001:
we can plug x=5.001
At x=4.9:
we can plug x=4.9
At x=4.95:
we can plug x=4.95
At x=4.99:
we can plug x=4.99
At x=4.995:
we can plug x=4.995
At x=4.999:
we can plug x=4.999