So it tell us that he is able to get 5 hits out of 7 and to find how much he could make if 210 chances

We solve what can be solved

Then we leave our variable alone

Last we solve

In this case we can see that he could make 147 hits out of 210 bats.
Answer:
48 bcoz u do 4(3)+5 do f(g) than for f(17) u do 3(17)-3
The fundamental theorem of algebra states that a polynomial with degree n has at most n solutions. The "at most" depends on the fact that the solutions might not all be real number.
In fact, if you use complex number, then a polynomial with degree n has exactly n roots.
So, in particular, a third-degree polynomial can have at most 3 roots.
In fact, in general, if the polynomial
has solutions
, then you can factor it as

So, a third-degree polynomial can't have 4 (or more) solutions, because otherwise you could write it as

But this is a fourth-degree polynomial.
Area of a square= l²
= 8×8 = 64 in²
Area of a circle= πr²
= π × 4²
= 50.3 in²
Difference = 64 - 50.3 = 13.7 in²