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3 years ago

5

If the length of the major axis of an ellipse is 28 units and the foci are located 3.5 units away from the center, what is the e

ccentricity of the ellipse?

2 answers:

guajiro [1.7K]3 years ago

6 0

Answer:0.25

Step-by-step explanation:

i hope this helps #platofam #platolivesmatter

Mandarinka [93]3 years ago

3 0

Eccentricity = foci / half the length of the major axis
= 3.5 / 14 = 1/4

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Consider the segment below.

mars1129 [50]

Answer:

B

Step-by-step explanation:

midpoint of EF: (-3,1/2)

distance of HG: 3.64

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3 years ago

If y varies inversely as x and y is 2.5 when x is 6, what is y when x is 4? a. 3.75 b. 1.67 c. 0.1 d. 7.5 Please select the best

REY [17]

Because y varies inversely as x, therefore
$y= \frac{k}{x}$
where k = constant.

When x = 6, y = 2.5. Ther efore
$\frac{k}{6} = 2.5$
Cross multiply.
k = 6 x 2.5 = 15

The equation is
$y = \frac{15}{x}$

When x = 4, obtain
$y = \frac{15}{4}= 3.75$

Answer: a. 3.75

8 0

3 years ago

Read 2 more answers

A retangle has an area of 30 square meters and a perimeter of 34 meters what are the dimensions of the retangle

s344n2d4d5 [400]

Answer: Length = 15 meters

Width = 2 meters

Step-by-step explanation:

Perimeter of a rectangle = 2l + 2w

Area of a rectangle = l × w

where l = length

w = width

Therefore,

2l + 2w = 34 ...... i

l × w = 30 ........ ii

From equation i

2l + 2w = 34

Divide through by 2.

l + w = 17 ...... iii

Then, l = 17 - w ........ iv

Put equation iv into ii

l × w = 30

(17 - w) × w = 30

17w - w² = 30

w² - 17w + 30 = 0

w² - 15w - 2w + 30 = 0

w(w - 15) - 2(w - 15) = 0

(w - 2) = 0

w = 0 + 2 = 2

w - 15 = 0

w = 0 + 15 = 15

Length = 15 meters

Width = 2 meters

6 0

3 years ago

Evaluate the question below<br> .<br> 12-2

MAXImum [283]

Answer:

=>12-2

=> 10

<em><u>You're Welcome</u></em>

<em><u>Hope this helps you.</u></em>

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3 years ago

under a dilation, the point (2,6) is moved to (6,18) what is the scale factor of the dilation? enter your answer in the box

Anestetic [448]

<h2>3</h2>

Step-by-step explanation:

The equation of line passing through the two points is $\frac{y-y_{1} }{x-x_{1} }=\frac{y_{2} -y_{1}}{x_{2} -x_{1}}$

When substituted,the equation becomes $\frac{y-6}{x-2}=\frac{18-6}{6-2}$

which when simplified is $y=3\times x$

The line clearly passes through origin.

The distance between two points is $\sqrt{(y_{1}-y_{2} )^{2}+(x_{1}- x_{2} )^{2}}$

Distance between origin and $(2,6)$ is $\sqrt{40}$ .

Distance between origin and $(6,18)$ is $\sqrt{360}$

Scale factor is $\frac{distance\text{ }of\text{ }p_{2}\text{ from origin}}{distance \text{ } of \text{ } p_{1}\text{ from origin}}$

So,scale factor is $\frac{\sqrt{360} }{\sqrt{40} }$

which when simplified becomes 3.

6 0

3 years ago