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aleksklad [387]
3 years ago
5

1/4,5/8,1/2 I need the fractions in least to greatest

Mathematics
2 answers:
notsponge [240]3 years ago
5 0
1/4 then 5/8 then 1/2...
djyliett [7]3 years ago
4 0
1/4 is the least, 1/2 is next, then 5/8 as the greatest.
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Convert the following equation<br> into standard form.<br> y = 7 - 7x<br> [?]x + y = []
Tanzania [10]

Answer:

y = 7 - 7x \\ y + 7x = 7 \\ 7x + y = 7

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PLZ HELP FAST <br> Find the difference of 36.598 - 0.001
Radda [10]

Answer:

36.598 - 0.001 = 36.597

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7. Solve by factoring. n² + 2n – 24 = 0 (1 point). A. –12, 2. B.–2, 12. C.–6, 4. D.–4, 6
Wittaler [7]
<span>n² + 2n – 24=0
</span><span>n² + 6n-4n – 24=0
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3 years ago
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The circumference of a sphere was measured to be 90 cm with a possible error of 0.5 cm.
Akimi4 [234]

Answer:

Error in the sphere's surface: 29 cm^2  and relative error in surface measure: 0.011

Error in the sphere's volume: 205 cm^3 and relative error in the volume measure: 0.017

Step-by-step explanation:

(a)

The measured length (l) of the circumference is 90 cm with an error of 0.5 cm, that is:

l=2\,\pi\,R=90\,cm\\R=\frac{90}{2\,\pi} \,cm=\frac{45}{\pi} \,cm=14.3239\,\,cm

and with regards to the error:

dl=0.5 \, cm\\dl=2\,\pi\,dR\\dR=\frac{dl}{2\,\pi} =\frac{1}{4\,\pi} cm = 0.0796\,cm

then when we use the formula for the sphere's surface, we get:

S=4\,\pi\,R^2\\dS=4\,\pi\,2\,R\,(dR)\\dS=8\,\,\pi\.(\frac{45}{\pi} \,\,cm)\,(\frac{1}{4\pi}\,cm) =\frac{90}{\pi} \,\,cm^2\approx \,29\,cm^2

Then the relative error in the surface is:

\frac{dS}{S} =\frac{90/\pi}{4\,\pi\,R^2} =\frac{1}{90} =0.011

(b)

Use the formula for the volume of the sphere:

V=\frac{4\,\pi}{3} R^3\\dV=\frac{4\,\pi}{3}\,3\,R^2\,(dR)=4\,\pi\,R^2\,(\frac{1}{4\pi}) \,cm=(\frac{45}{\pi})^2 \,\,cm^3\approx 205\,\,cm^3

Then the relative error in the volume is:

\frac{dV}{V} =\frac{205}{12310.5} \approx 0.017

3 0
3 years ago
2/5 simply to a decimal
Nadusha1986 [10]
Your answer is 0.40 ......................
5 0
3 years ago
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