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ddd [48]
3 years ago
15

What number should both sides of the following equation be divided by to solve for x?

Mathematics
2 answers:
erik [133]3 years ago
7 0
You have to divide 6.4 to both sides
iVinArrow [24]3 years ago
5 0
The number that should be used is 6.4
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In an election, ethan got 5 fewer votes than christohper,who got 3 more votes than olivia, who got 4 fewer votes than Ava.
Zina [86]

Answer:

110 votes

Step-by-step explanation:

110 votes

8 0
3 years ago
Solve the proportion for t 15:75=30:t
Dominik [7]
The answer is 150.
15(2)=30 so
75(2) is 150
5 0
3 years ago
Special Triangles
Ugo [173]

Answer:

see explanation

Step-by-step explanation:

Using the cosine and tangent trigonometric ratios and the exact values

cos30° = \frac{\sqrt{3} }{2} and tan30° = \frac{1}{\sqrt{3} } , then

cos30° = \frac{adjacent}{hypotenuse} = \frac{6}{m} = \frac{\sqrt{3} }{2} ( cross- multiply )

\sqrt{3} × m = 12 ( divide both sides by \sqrt{3} )

m = \frac{12}{\sqrt{3} } ← rationalise by multiplying numerator/ denominator by \sqrt{3} )

m = \frac{12}{\sqrt{3} } × \frac{\sqrt{3} }{\sqrt{3} } = \frac{12\sqrt{3} }{3} = 4\sqrt{3}

-------------------------------------------------------------------------------

tan30° = \frac{opposite}{adjacent} = \frac{n}{6} = \frac{1}{\sqrt{3} } ( cross- multiply )

\sqrt{3} × n = 6 ( divide both sides by \sqrt{3} )

n = \frac{6}{\sqrt{3} } ← rationalise the denominator

n = \frac{6}{\sqrt{3} } × \frac{\sqrt{3} }{\sqrt{3} } = \frac{6\sqrt{3} }{3} = 2\sqrt{3}

-----------------------------------------------------------------------------------

7 0
3 years ago
The leg of a right triangle are 3 units and 10 units. What is the length of the hypotenuse? Round your answer to the nearest hun
Andreas93 [3]
Hey there! This is gonna require the Pythagorean Theorem which is<span> a^2 + b^2 = c^2
</span>
a and b in this case are the legs while c is the hypotenuse! So, we can just plug in the numbers we know!

3^2 + 10^2 = c^2

9 + 100 = c^2

109 = c^2

And then take the square root of 109 to get the hypotenuse.

<span>10.4403065089 = c
</span>
Since we need to round to the nearest hundredth, though, it would be 10.44



I hope that helps! Feel free to let me know if you have any questions!

- mathwizzard3
6 0
3 years ago
According to the National Center for Health​ Statistics, in​ 1990, 28 % of babies in the United States were born to parents who
AfilCa [17]

Answer:

76 % of babies will be born out of​ wedlock in the 81^{st} year

Step-by-step explanation:

Given:  In​ 1990, 28 % of babies in the United States were born to parents who were not married. This increased by approximately 0.6 % per year.

To find: year when 76 % of babies born out of​ wedlock

Solution:

A sequence is said to be in arithmetic progression if the difference between the terms is same.

For a sequence with first term as 'a' and common difference as 'd', the nth term is given by a_n=a+(n-1)d

The given situation also forms an arithmetic progression with  a=28\,,\,d=0.6

Also, put a_n=76

So,

a_n=a+(n-1)d\\76=28+(n-1)(0.6)\\76-28=0.6(n-1)\\48=0.6(n-1)\\\frac{48}{0.6}=n-1\\\\80=n-1\\n=80+1\\n=81

So, 76 % of babies will be born out of​ wedlock in the 81^{st} year

6 0
3 years ago
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