Can you all help on 2-4 please
1 answer:
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Answer:
See the attached figure which represents the problem.
As shown, AA₁ and BB₁ are the altitudes in acute △ABC.
△AA₁C is a right triangle at A₁
So, Cos x = adjacent/hypotenuse = A₁C/AC ⇒(1)
△BB₁C is a right triangle at B₁
So, Cos x = adjacent/hypotenuse = B₁C/BC ⇒(2)
From (1) and (2)
∴ A₁C/AC = B₁C/BC
using scissors method
∴ A₁C · BC = B₁C · AC
Answer:
14.13 ft²
Step-by-step explanation:
The area of a semicircle is
We were given the radius of the semicircle to be: r=3 feet.
We were also asked to use π as 3.14.
We substitute into the formula to get:
This is the same as:
Or
The area of the semicircle is 14.13 ft²
Hey there!
The formula for the volume of a cone is .
In this cone, we have the given information:
- Its diameter is 4 inches
- Its height is 6 inches
The information we need for this formula is the radius and height.
We already have the height, but not the radius.
Fortunately, we can easily get it by dividing the diameter by 2.
So, the radius is 2.
Let 3.14 be .
Plug in each value into the equation.
Simplify the exponent and fraction.
Multiply the three numbers together.
But wait! We have to round this to the nearest tenth.
When rounding, we look at the place value one less than the one we are rounding to. Since we are rounding to the nearest tenth, we look at the hundredths place, which is the digit 2.
Since 2 is less than 5, we round down to 25.1.
This is the volume of a cube, and it is measured in inches, so the unit we will use is .
So, your <u>final answer</u> is !
Hope this helps!