Okay, So We Need To Remember The Formula.
I = P * R * T
So, We Plug In The Known Values.
P = 290
R = 3.3%
T = 2 years.
Simplify along the way.
I = 290 * 3.3% * 2
I = 290 * 0.033 * 2
I = 9.57 * 2
I = 19.14
Cos(theta)=-0.96 <0
=>
theta is either in the 2nd or third quadrant.
cos(theta)=-0.96
=>
sec(theta)=1/cos(theta)=-1/0.96 <0
Given sec(theta)(sin(theta)>0
=> cos(theta)sin(theta)>0
=> cos(theta) and sin(theta) have the same sign,
=> sin(theta)<0
=>
theta is in the third quadrant. => tan(theta)>0
Given cos(theta)=-0.96
=>
|sin(theta)|=sqrt(1-(-0.96)^2)=sqrt(0.0784)=0.28
=> sin(theta)=-0.28
Finally,
tan(theta)=sin(theta)/cos(theta)=-0.28/-0.96
=7/24
=0.29167 (to the fifth decimal place)
Answer:
Step-by-step explanation:
Given
Required
Write an inequality to represent the scenario?
Represent the additional number of pounds with p.
When p is added to the current pounds, the weight must be less than or equal to the total possible weights
In other words:
Substitute values for current and total
Hence, the inequality that describes the scenario is:
