What is a network of high-capacity communication links is the internet?

The overall cost of wiring in addressable fire alarm system is significantly cheaper than the conventional one. Why is it so?

stellarik [79]

Answer:

Yes, The overall cost of wiring in addressable fire alarm system is significantly cheaper than the conventional one.But the addressale fire alram system is more reliable than a conventional system.

Explanation:

Conventional systems are hardware-based and use analog technology. where addressable fire alarm use digital technology. addressable system is generally more reliable than a conventional system mainly due to how the different systems are wired. With a conventional system, if a device’s wire is damaged or severed, its signal and the signal of other devices down the line cannot be transmitted to the control panel.

With an addressable system, both ends of the wire connect to the control panel. Therefore, if one end becomes damaged or severed, signals can still reach the control panel through the other end of the loop. In addressable systems, a device can be removed or disabled and it will not affect the other devices in the loop.

7 0

3 years ago

In what real-life situations might you want to use the modulus operation in a program?

KonstantinChe [14]

Answer:

Since any even number divided by 2 has a remainder of 0, we can use modulo to determine the even-ess of a number. This can be used to make every other row in a table a certain color, for example.

5 0

2 years ago

Once a virus has been removed by your anti-virus program, all traces of it are gone from your computer.

pychu [463]

Im pretty sure that is false

5 0

3 years ago

Oxnard Casualty wants to ensure that their e-mail server has 99.98 percent reliability. They will use several independent server

sattari [20]

Answer:

The smallest number of servers required is 3 servers

Explanation:

Given

$Reliability = 99.98\%$

$Individual Servers = 95\%$

Required

Minimum number of servers needed

Let p represent the probability that a server is reliable and the probability that it wont be reliable be represented with q

Such that

$p = 95\%\\$

It should be noted that probabilities always add up to 1;

So,

$p + q = 1$ '

Subtract p from both sides

$p - p + q = 1 - p$

$q = 1 - p$

Substitute $p = 95\%\\$

$q = 1 - 95\%$

Convert % to fraction

$q = 1 - \frac{95}{100}$

Convert fraction to decimal

$q = 1 - 0.95$

$q = 0.05$

------------------------------------------------------------------------------------------------

To get an expression for one server

The probabilities of 1 servers having 99.98% reliability is as follows;

$p = 99.98\%$

Recall that probabilities always add up to 1;

So,

$p + q = 1$

Subtract q from both sides

$p + q - q = 1 - q$

$p = 1 - q$

So,

$p = 1 - q = 99.98\%$

$1 - q = 99.98\%$

Let the number of servers be represented with n

The above expression becomes

$1 - q^n = 99.98\%$

Convert percent to fraction

$1 - q^n = \frac{9998}{10000}$

Convert fraction to decimal

$1 - q^n = 0.9998$

Add $q^n$ to both sides

$1 - q^n + q^n= 0.9998 + q^n$

$1 = 0.9998 + q^n$

Subtract 0.9998 from both sides

$1 - 0.9998 = 0.9998 - 0.9998 + q^n$

$1 - 0.9998 = q^n$

$0.0002 = q^n$

Recall that $q = 0.05$

So, the expression becomes

$0.0002 = 0.05^n$

Take Log of both sides

$Log(0.0002) = Log(0.05^n)$

From laws of logarithm $Loga^b = bLoga$

So,

$Log(0.0002) = Log(0.05^n)$ becomes

$Log(0.0002) = nLog(0.05)$

Divide both sides by $Log0.05$

$\frac{Log(0.0002)}{Log(0.05)} = \frac{nLog(0.05)}{Log(0.05)}$

$\frac{Log(0.0002)}{Log(0.05)} = n$

$n = \frac{Log(0.0002)}{Log(0.05)}$

$n = \frac{-3.69897000434}{-1.30102999566}$

$n = 2.84310893421$

$n = 3 (Approximated)$

Hence, the smallest number of servers required is 3 servers

6 0

3 years ago

In Python, if var1 = "Happy" and var2= "Birthday" and var3 = (var 1+var2) *2, then var3 stores the string

nordsb [41]

Answer:

The answer is "Option A".

Explanation:

The program to the given question can be given as:

program:

var1 = "Happy" #defining variable var1

var2= "Birthday" #defining variable var2

var3 = (var1+var2) *2 #defining variable var3 and calculate value

print (var3) #print value.

Output:

HappyBirthdayHappyBirthday

In the above python program, three variable is defined, that is var1, var2, and var3, in which variable var1 and var2 we assign a value, that is "Happy" and "Birthday".

In variable var3 we add the value of var1 and var2 variable and multiply by 2. It will print the variable value two times. and other options are not correct that can be defined as:

In option B and C, Both variable var1 and var2 print there values two times but in option B var1 value print two time and var2 value print one time only and option C var1 variable value is print only one time and var2 variable value is print two times that's why it is not correct.
In option C, Both variable var1 and var2 print there values two times that's why it is not correct.

7 0

3 years ago