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galben [10]
3 years ago
6

What is the property of the Magnetic Lasso tool?

Computers and Technology
2 answers:
alexandr402 [8]3 years ago
8 0

Answer:

Your answer would be D.lets you select part of an image by automatically tracing outlines

Explanation:

Well, unlike the standard Lasso Tool which gives you no help at all and relies entirely on your own ability to manually trace around the object, usually with less than stellar results, the Magnetic Lasso Tool is an edge detection tool, meaning that it actively searches for the edge of the object as you're moving around

AnnZ [28]3 years ago
7 0
The answer is letter d. <span>lets you select part of an image by automatically tracing outlines.

</span><span>A magnetic lasso is a tool used in Photoshop used to automatically identify the edges and parts like a magnet spotting and clinging. </span><span> It comes in handy when selecting the part of the image and to specifically apply the needed editing on it. </span><span>
</span><span>
</span><span>
</span><span>
</span>
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Noticing his reduced performance at work, Dan enrolled himself for training sessions offered by the company and saw his producti
Luden [163]

A. self-efficacy.

B. overreward inequity.

C. expectancy.

D. cognitive distortion.

Answer:B. overreward inequity.

Explanation: Overreward inequity is a term mostly associated with the feeling of guilt by an employee who believes that his contributions to work or his performance rating is less than what he or she is been paid for.

An employee with this kind of guilt feelings will mostly like do his or her best to engage in in performance improvement Activities which includes enrollment for training and classes to enhance his or her performance.

6 0
3 years ago
Create an array of numbers filled by the random number generator. (value = (int)(Math.random() * 100 + 1);) Print the array and
Y_Kistochka [10]

Answer:

Explanation:

the following is the code to run this (JAVA)

MeanStandardDev.java

import java.util.Random;

import java.util.Scanner;

public class MeanStandardDev {

public static void main(String[] args) {

// Declaring variables

int N;

double lower, upper, min, max, mean, stdDev;

/*

* Creating an Scanner class object which is used to get the inputs

* entered by the user

*/

Scanner sc = new Scanner(System.in);

// Getting the input entered by the user

System.out.print(" How many Random Numbers you want to generate :");

N = sc.nextInt();

System.out.print("Enter the Lower Limit in the Range :");

lower = sc.nextDouble();

System.out.print("Enter the Upper Limit in the Range :");

upper = sc.nextDouble();

// Creating Random class object

Random rand = new Random();

double nos[] = new double[N];

// this loop generates and populates 10 random numbers into an array

for (int i = 0; i < nos.length; i++) {

nos[i] = lower + (upper - lower) * rand.nextDouble();

}

//calling the methods

min = findMinimum(nos);

max = findMaximum(nos);

mean = calMean(nos);

stdDev = calStandardDev(nos, mean);

//Displaying the output

System.out.printf("The Minimum Number is :%.1f\n",min);

System.out.printf("The Maximum Number is :%.1f\n",max);

System.out.printf("The Mean is :%.2f\n",mean);

System.out.printf("The Standard Deviation is :%.2f\n",stdDev);

}

//This method will calculate the standard deviation

private static double calStandardDev(double[] nos, double mean) {

//Declaring local variables

double standard_deviation=0.0,variance=0.0,sum_of_squares=0.0;

/* This loop Calculating the sum of

* square of eeach element in the array

*/

for(int i=0;i<nos.length;i++)

{

/* Calculating the sum of square of

* each element in the array    

*/

sum_of_squares+=Math.pow((nos[i]-mean),2);

}

//calculating the variance of an array

variance=((double)sum_of_squares/(nos.length-1));

//calculating the standard deviation of an array

standard_deviation=Math.sqrt(variance);

return standard_deviation;

}

//This method will calculate the mean

private static double calMean(double[] nos) {

double mean = 0.0, tot = 0.0;

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Calculating the sum of all the elements in the array

tot += nos[i];

}

mean = tot / nos.length;

return mean;

}

//This method will find the Minimum element in the array

private static double findMinimum(double[] nos) {

double min = nos[0];

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Finding minimum element

if (nos[i] < min)

min = nos[i];

}

return min;

}

//This method will find the Maximum element in the array

private static double findMaximum(double[] nos) {

double max = nos[0];

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Finding minimum element

if (nos[i] > max)

max = nos[i];

}

return max;

}

}

the OUTPUT should give;

How many Random Numbers you want to generate :10

Enter the Lower Limit in the Range :1.0

Enter the Upper Limit in the Range :10.0

The Minimum Number is :1.1

The Maximum Number is :9.9

The Mean is :6.30

The Standard Deviation is :2.98

cheers i hope this helps!!!

4 0
3 years ago
In this scenario, two friends are eating dinner at a restaurant. The bill comes in the amount of 47.28 dollars. The friends deci
pickupchik [31]

Answer:

The java program for the given scenario is as follows.

import java.util.*;

import java.lang.*;

public class Main

{

   //variables for bill and tip declared and initialized

   static double bill=47.28, tip=0.15;

   //variables for total bill and share declared

   static double total, share1;

public static void main(String[] args) {

    double total_tip= (bill*tip);

    //total bill computed

    total = bill + total_tip;

    //share of each friend computed

    share1 = total/2;

    System.out.printf("Each person needs to pay: $%.2f", share1);  

}

}

Explanation:

1. The variables to hold the bill and tip percent are declared as double and initialized with the given values.

static double bill=47.28, tip=0.15;

2. The variables to hold the values of total bill amount and total tip are declared as double.

3. All the variables are declared outside main() and at class level, hence declared as static.

4. Inside main(), the values of total tip, total bill and share of each person are computed as shown.

double total_tip= (bill*tip);

total = bill + total_tip;

share1 = total/2;

5. The share of each person is displayed to the user. The value is displayed with only two decimal places which is assured by %.2f format modifier. The number of decimal places required can be changed by changing the number, i.e. 2. This format is used with printf() and not with println() method.

System.out.printf("Each person needs to pay: $%.2f", share1);  

6. The program is not designed to take any user input.

7. The program can be tested for any value of bill and tip percent.

8. The whole code is put inside a class since java is a purely object-oriented language.

9. Only variables can be declared outside method, the logic is put inside a method in a purely object-oriented language.

10. As shown, the logic is put inside the main() method and only variables are declared outside the method.

11. Due to simplicity, the program consists of only one class.

12. The output is attached.

5 0
3 years ago
Read 2 more answers
Which of the following groups would an animal with an exoskeleton, segmented body, and jointed appendages belong to???
Annette [7]
All arthropods have exoskeletons, like insects, spiders and crustaceans.
7 0
3 years ago
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Using the XML Document below (library with books), define the following queries in XQuery: (a) Give the titles of all Books sort
Softa [21]

Answer:

Explanation:

a)use order by clause for sorting

for $x in doc("books.xml")/bib/book order by xs:float($x/price) return $x/title (default sorted in ascending order)

or

for $x in doc("books.xml")/bib/book order by xs:float($b/price) descending  return $b/title (sorted in descending order)

b)doc("books.xml")//book[author = 'Abiteboul']

c)for $x in distinct-values(doc("bib.xml")/bib/book/author)

return <res>

<name>{$x}</name>

<count>

 {count (doc("bib.xml")//book[exists(indexof(author,$x))]) }

</count>

<res>

3 0
3 years ago
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