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3 years ago

Which expression is equivalent to 4(9x2−2)? 36x2−10−2 16x2+14−20x2−2 18x2−12−18x2+2 30x2−10+6x2+2

Mathematics

2 answers:

Snowcat [4.5K]3 years ago

6 0

Answer:

4(9×2-2)

= 36×8-8

= 288-8

= 280

Yanka [14]3 years ago

3 0

Answer:

the answer is $36x^2-10+2$

Step-by-step explanation:

$4(9x^2-2)=36x^2-8=36x^2-10+2$

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What is the solution for 3x-4=-1/2x+3

prohojiy [21]

Answer:

Step-by-step explanation:

3x-4 =-1/2x+3

3x+1/2x=3+4

6x+x/2=7

6x+x=14

7x=14

x=14/2

x= 2

4 0

2 years ago

Read 2 more answers

What is the range of the function y = x 2?

Leno4ka [110]

Answer:

$\mathrm{Range\:of\:}x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}$

The graph is also attached below.

Step-by-step explanation:

Given the function

$y=x^2$

We know that the range of a function is the set of values of the dependent variable for which a function is defined.

$\mathrm{For\:a\:parabola}\:ax^2+bx+c\:\mathrm{with\:Vertex}\:\left(x_v,\:y_v\right)$

$\mathrm{If}\:a$

$\mathrm{If}\:a>0\:\mathrm{the\:range\:is}\:f\left(x\right)\ge \:y_v$

$a=1,\:\mathrm{Vertex}\:\left(x_v,\:y_v\right)=\left(0,\:0\right)$

$f\left(x\right)\ge \:0$

Thus,

$\mathrm{Range\:of\:}x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}$

The graph is also attached below.