Answer:
Jason travels 0.16 miles
Step-by-step explanation:
hope this helps :)
Replace <span><span>f<span>(x)</span></span><span>fx</span></span> with <span>yy</span>.<span><span>y=<span><span>6<span>x3</span></span><span>−8</span></span></span><span>y=<span><span>6<span>x3</span></span><span>-8</span></span></span></span>Interchange the variables.<span><span>x=<span><span>6<span>y3</span></span><span>−8</span></span></span><span>x=<span><span>6<span>y3</span></span><span>-8</span></span></span></span>Solve for <span>yy</span>.
<span><span>y=<span><span>3<span>√<span>36<span>(<span>x+8</span>)</span></span></span></span>6</span></span><span>y=<span><span><span>36<span>x+8</span></span>3</span>6</span></span></span>Solve for <span>yy</span> and replace with <span><span><span>f<span>−1</span></span><span>(x)</span></span><span><span>f<span>-1</span></span>x</span></span>.
<span><span><span>f<span>−1</span></span><span>(x)</span></span>=<span><span>3<span>√<span>36<span>(<span>x+8</span>)</span></span></span></span><span>6</span></span></span>
Wheres the rest of the problem? or is this it?
To start off, you need to take the cube root of both sides of the equation.
![\sqrt[3]{x} = \frac{ \sqrt[3]{27} }{ \sqrt[n]{64} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%7D%20%3D%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7B27%7D%20%7D%7B%20%5Csqrt%5Bn%5D%7B64%7D%20%7D%20)
The cube root of 27 is 3, and the cube root of 64 is 4.
The answer would then be x=3/4
Answer:
40
Step-by-step explanation:
im not 100% sure, but I think it's 40
