Given:
t1 = 3.6 h
t2 = 4.5 h
x = speed of boat
y = speed of water
Required:
a) Expression of distance traveled with moving water with 3.6h
Expression of distance traveled with moving water with 4.5h
b) Solve for y
c) Percent of boat's speed is the water current
Solution:
Working formula: distance = velocity*time
a) For travelling downstream, we get the equation
d = (x +y)*3.6
For travelling upstream, we get the equation
d = (x-y)*4.5
b) Setting the distance as equal for travelling upstream or downstream, we arrive at the equation of
(x+y)*3.6 = (x-y)*4.5
3.6x + 3.6y = 4.5x - 4.5y
8.1y =0.9x
y = x/9
c) percentage = 1/9*100% = 11.1%
<em>ANSWERS: a) d = (x+y)*36; d = (x-y)*4.5
</em> <em>b) y = x/9
</em> <em>c) 11.1%</em>
Answer:
D
Step-by-step explanation:
6% of 40 is 2.4, 40.00+ 2.40=42.40
Answer:
11,200
Step-by-step explanation:
At first we use "BODMAS" rule.
Given,
(3.5×10^13)-(1.4×10^12)/3×10^9
So, we will break the brackets at first. With the help of excel, we can get the desired result. The following images will show you the step-by-step result.
Use "Number" instead of "general" in the excel sheet. You can use calculator too.
Replace all the x values with -3
f(-3)=-2(-3)^2+5(-3)
f(-3)=2(9)-15
f(-3)=18-15
f(-3)=3
Hope I helped :)
