A1. 12 i.e option D
A2. 3n-7 i.e option A
A3. -6n+20 i.e option D
A4. -70 i.e option C
Step-by-step explanation:
aₙ = a₁ + (n - 1) × d
aₙ = the nᵗʰ term in the sequence
a₁ = the first term in the sequence
d = the common difference between terms
Using the above formula to solve the first part, we have :
For the second part, we have :
For the third part, we have :
For the fourth part, we have :
F(x)·g(x) = (3x-2)(5x) = 15x^2 -10x
Answer:
b^2-4b+3=0
b²-3x-b+3=0
b(b-3)-1(b-3)=0
(b-3)(b-1)=0
either
b=3 or b=1
.
2n^2 + 7 = -4n + 5
2n²+4n+7-5=0
2n²+4n+2=0
2(n²+2n+1)=0
(n+1)²=0/2
:.n=-1
.
x - 3x^2 = 5+ 2x - x^2
0=5+ 2x - x^2-x +3x^2
0=5+x+2x²
2x²+x+5=0
comparing above equation with ax²+bx +c we get
a=2
b=1
c=5
x={-b±√(b²-4ac)}/2a ={-1±√(1²-4×2×5)}/2×1
={-1±√-39}/2
Answer:
The 32nd term of Arithmetic sequence is -174
Step-by-step explanation:
Given: 
We are given two term of the Arithmetic sequence.
Formula:
For 
For 
Using two equation solve for a and d
We need to find 32nd term
Hence, The 32nd term of Arithmetic sequence is -174
Answer:
x <4
Step-by-step explanation:
2x-9<-1
Add 9 to each side
2x-9+9<-1+9
2x < 8
Divide each side by 2
2x/2 < 8/2
x <4
