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2 years ago

12

Find the zeros of the polynomial function f(x)=x^4-5x^3+11x^2-25x+30

1 answer:

krek1111 [17]2 years ago

8 0

Found one... after the 3

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Pls can someone help me<br><img src="https://tex.z-dn.net/?f=%20log10%20%5Csqrt%7B36%7D%20%20%2B%20%20%20%20log10%20%20%5Csqrt%7

Firlakuza [10]

Answer:

$= log_{10}(\frac{6\sqrt{2} }{\sqrt{7} } )$

Step-by-step explanation:

Given the expression $log10\sqrt{36} + log10\sqrt{2} - log10\sqrt{7} \\$

According to the law of logarithm;

loga + log b = log(ab) and log a - log b = log(a/b)

The given expression becomes;

$log10\sqrt{36} + log10\sqrt{2} - log10\sqrt{7} \\= log_{10}(\frac{\sqrt{36} \times \sqrt{2} }{\sqrt{7} })\\= log_{10}(\frac{6\sqrt{2} }{\sqrt{7} } )$

6 0

2 years ago

Calculate the size of each interior angle of a regular polygon with 14 sides

Ierofanga [76]

Answer:

154.285

Step-by-step explanation:

The sum of the interior angles of a 14-gon = (14-2)*180 = 2,160 degrees. There are 14 vertexes (vertices) for a 14-gon. It is 'regular' so all these angles are equal. By dividing 2160 (sum of all angles) by 14 (total amount of angles) we can see how much each angle is worth. So the interior angle of each is 154.285 degrees.

4 0

2 years ago

Using the formula C = 2πr, find the circumference of a circle with diameter of 28 inches. Round your answer to the nearest inch.

Paraphin [41]

Answer:

88 inches

Step-by-step explanation:

Diameter is 2 times the radius (r) so divided 28 by 2 to get 14 as the radius.

Plug this in:

2π14

28π

87.964

88

6 0

2 years ago

Read 2 more answers

If the area of AABC is D, give the expressions that complete the equation for the measure of ZB?

Ira Lisetskai [31]

Given:

The figure of triangle ABC.

The area of the triangle ABC is D.

$m\angle B=\sin ^{-1}(\dfrac{m}{n})$

To find:

The value of m and n in the given expression.

Solution:

Let h be the height of the triangle ABC.

Area of a triangle is:

$Area=\dfrac{1}{2}\times base\times h$

Where, b is the base and h is the height of the triangle.

$Area=\dfrac{1}{2}\times a\times h$

The area of the triangle ABC is D.

$D=\dfrac{1}{2}\times a\times h$

$2D=ah$

$\dfrac{2D}{a}=h$ ...(i)

In a right angle triangle,

$\sin \theta =\dfrac{Perpendicular}{Hypotenuse}$

$\sin B =\dfrac{h}{c}$

$\sin B =\dfrac{1}{c}\times \dfrac{2D}{a}$ [Using (i)]

$\sin B =\dfrac{2D}{ac}$

$m\angle B =\sin ^{-1}\dfrac{2D}{ac}$ ...(ii)

We have,

$m\angle B=\sin ^{-1}(\dfrac{m}{n})$ ...(iii)

On comparing (ii) and (iii), we get

$m=2D$

$n=ac$

Therefore, the required values are $m=2D, n=ac$ .

6 0

2 years ago

The radius of a circle is decreasing at a rate of 6.56.56, point, 5 meters per minute. At a certain instant, the radius is 12121

Ilia_Sergeevich [38]

Answer:

The rate of change of the area of the circle is approximately $-490.09 \ m^2/min$ .

Step-by-step explanation:

Given:

$\frac{dr}{dt} = -6.5 \ m/min$

radius $r =12 \ m$

We need to find the rate of change of the area of the circle at that instant.

Solution:

Now we know that;

Area of the circle is given by π times square of the radius.

framing in equation form we get;

$A= \pi r^2$

to find the rate of change of the area of the circle at that instant we need to take the derivative on both side.

$\frac{dA}{dt}=\frac{d(\pi r^2)}{dt}\\\\\frac{dA}{dt}= 2\pi r \frac{dr}{dt}$

Substituting the given values we get;

$\frac{dA}{dt}= 2\times \pi \times 12 \times -6.5\\\\\frac{dA}{dt}\approx -490.09 \ m^2/min$

Hence The rate of change of the area of the circle is approximately $-490.09 \ m^2/min$ .

6 0

2 years ago