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laila [671]
3 years ago
12

Find the zeros of the polynomial function f(x)=x^4-5x^3+11x^2-25x+30

Mathematics
1 answer:
krek1111 [17]3 years ago
8 0
Found one... after the 3
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In the triple beam balance, what is the appropriate number of decimal places?
Lyrx [107]

Answer:

Then the correct answer would be to two decimal places. Credit to 25rx0162.

Step-by-step explanation

Hope this helps : )

4 0
3 years ago
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Write the equation of the line that passes through (3, 4) and (2, –1) in slope-intercept form.
matrenka [14]
1) slope is 6 and y-intercept is ( 0,5)    y = mx + b, m = 6, b = 5    y = 6x + 5 2)line passes through the points ( 3,6) and ( 6,3 )   First find the slope:  m = (3-6)/(6-3) = -3/3 = -1   y = -x + b   Plug in one of the given points (x,y) and find b   6 = -3 + b   9 = b  <span> y = -x + 9</span> a horizontal line that passes through the point ( -1,7)Horizontal lines have a constant y-value and formaty = c  where c is a constant number. y = 7 y=-3x+3x intercept:  set y = 0 and solve for x0 = -3x + 33x = 3x = 1x-intercept: (1, 0) y-intercept:  set x = 0 and solve for yy = -3(0) + 3y = 3y-intercept: (0,3) y=0,5x-1Is this two equations? The line y=0 has y-intercept at (0,0)The x-intercept is the entire x-axis y=5x-1x -intercept:  Set y = 0 and solve for x y-intercept: Set x = 0 and solve for y 
5 0
3 years ago
(-3)³ + (-4)² - (-2)³
AleksAgata [21]

Answer:

=-3

Step-by-step explanation:

\left(-3\right)^3+\left(-4\right)^2-\left(-2\right)^3\\Follow\:the\:PEMDAS\:order\:of\:operations\\\mathrm{Calculate\:exponents}\:\left(-3\right)^3\::\quad -27\\\left(-3\right)^3\\\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=-a^n,\:\mathrm{if\:}n\mathrm{\:is\:odd}\\\left(-3\right)^3=-3^3=-27\\=-27+\left(-4\right)^2-\left(-2\right)^3\\\mathrm{Calculate\:exponents}\:\left(-4\right)^2\::\quad 16\\\left(-4\right)^2

\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=a^n,\:\mathrm{if\:}n\mathrm{\:is\:even}\\\left(-4\right)^2=4^2=16\\=-27+16-\left(-2\right)^3\\\mathrm{Calculate\:exponents}\:\left(-2\right)^3\::\quad -8\\\left(-2\right)^3\\\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=-a^n,\:\mathrm{if\:}n\mathrm{\:is\:odd}\\\left(-2\right)^3=-2^3=-8\\=-27+16-\left(-8\right)\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:-27+16-\left(-8\right)\::\quad -3\\-27+16-\left(-8\right)

-27+16=-11\\=-11-\left(-8\right)\\\mathrm{Apply\:rule\:}-\left(-a\right)\:=\:+a\\-\left(-8\right)=+8\\=-11+8\\-11+8=-3\\=-3

8 0
3 years ago
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A triangle has an angle that measures 90°. The other two angles are in a ratio of 2:7. What are the measures of those two angles
marin [14]

Answer:

70° and 20°

let the other 2 angles be 7x and 2x

90+7x+2x=180

9x=180-90

x=90/9

x=10

7x=7x10

70

2x=2×10

2p

3 0
2 years ago
16 x - 4y = 3 <br>y = 4x + 7 ​
Damm [24]

Answer:

Step-by-step explanation:

7 0
3 years ago
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