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laila [671]
3 years ago
12

Find the zeros of the polynomial function f(x)=x^4-5x^3+11x^2-25x+30

Mathematics
1 answer:
krek1111 [17]3 years ago
8 0
Found one... after the 3
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before the recent house bonding there were 3212 houses in Fulton country now there are 3979 houses. How many houses did develope
lorasvet [3.4K]

Answer:

767 houses

Step-by-step explanation:

Initially there are 3212 houses in the city.

After the boom there are 3979 houses in the city.(due to boom there is an increase in the number of houses).

The number of houses developed by the developers is the difference between the number of houses before and after the boom.

The number of houses developed=3979-3212=767 houses

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3 years ago
WILL MARK U AS BRAINLIEST HELP PLZ. (Show work)
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Answer:

For #3 the answer is 113.04 (6 + g) / 32

Step-by-step explanation:

A = Pi * r * (r + g)

12/2 = 6 ft

A = 3.14 * (6) * (6 + g) = 113.04 (6 + g) square feet

113.04 (6 + g) / 32

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3 years ago
Find the least common multiple of these two expressions 8v^5w^8 and 14
Morgarella [4.7K]
True..............................................
4 0
3 years ago
In an arithmetic sequence, a17 = -40 and
Viktor [21]

Answer:

Tn = 2Tn-1 - Tn-2

Step-by-step explanation:

Before we can generate the recursive sequence, we need to find the nth term of the given sequence.

nth term of an AP is given as:

Tn = a+(n-1)d

If a17 = -40

T17 = a+(17-1)d = -40

a+16d = -40 ...(1)

If a28 = -73

T28 = a+(28-1)d = -73

a+27d = -73 ...(2)

Solving both equations simultaneously using elimination method.

Subtracting 1 from 2 we have:

27d - 16d = -73-(-40)

11d = -73+40

11d = -33

d = -3

Substituting d = -3 into 1

a+16(-3) = -40

a - 48 = -40

a = -40+48

a = 8

Given a = 8, d = -3, the nth term of the sequence will be

Tn = 8+(n-1) (-3)

Tn = 8+(-3n+3)

Tn = 8-3n+3

Tn = 11-3n

Given Tn = 11-3n and d = -3

Tn-1 = Tn - d... (3)

Tn-1 = 11-3n +3

Tn-1 = 14-3n

Tn-2 = Tn-2d...(4)

Tn-2 = 11-3n-2(-3)

Tn-2 = 11-3n+6

Tn-2 = 17-3n

From 3, d = Tn - Tn-1

From 4, d = (Tn - Tn-2)/2

Equating both common difference

(Tn - Tn-2)/2 = Tn - Tn-1

Tn - Tn-2 = 2(Tn - Tn-1)

Tn - Tn-2 = 2Tn-2Tn-1

2Tn-Tn = 2Tn-1 - Tn-2

Tn = 2Tn-1 - Tn-2

The recursive formula will be

Tn = 2Tn-1 - Tn-2

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3 years ago
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Estimate each product or quotient.
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23,307,609 that is the answer
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