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babunello [35]
3 years ago
12

Is this problem right because I need to know thanks!!

Mathematics
1 answer:
inna [77]3 years ago
8 0

Sadly, the answer to your question is 'No'.  The work written under
the problem on the paper is not correct ... because you tried to do
too much !

You can't combine 'm' terms with 'n' terms or with plain numbers.
They all need to stay separate all the way to the end.

So, actually, your first written line is the answer . . .  <em>7m - 35 + 3n</em>

That's as far as you can go.  You can't combine these terms. Stop there !


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A system of two linear equations and three unknowns can be solved by:
irakobra [83]
These cannot be solved.- 3 unknowns require 3 equations 
3 0
3 years ago
Please help !!!!!!! Will mark brainliest for the correct answer !!!!!!!!
Sholpan [36]

Answer:

Step-by-step explanation:

-2m - 5n = 7m - 3n

-9m - 5n = -3n

-9m = -2n

m = 2n/9

g(m)= 2n/9

7 0
3 years ago
Read 2 more answers
Una empresa fabrica dos productos, X y Y. Cada cantidad del articulo X producida requiere dos horas de trabajo en una taladrador
Zarrin [17]

Answer:

la respuesta esta abajo

Step-by-step explanation:

a) Sea x el número del artículo x mientras que y representa el número del artículo y.

Dado que cada cantidad de artículo x requiere 2 horas de trabajo de perforación, mientras que cada cantidad de artículo y requiere 5 horas de trabajo de perforación. Hay un máximo de 40 horas disponibles, por tanto el modelo se da como:

2x + 5y ≤ 40

b) La trama se trazó utilizando la herramienta gráfica en línea de geogebra.

c) Para 10 unidades de X y 5 unidades de y:

2 (10) + 5 (5) = 45> 40

Por lo tanto, esto no sería posible porque requerirá 45 horas de perforación, lo que es más que el máximo de 40 horas disponibles.

8 0
3 years ago
Which table does NOT represent a linear function?
chubhunter [2.5K]

Hey there!
Linear functions have a continuous change.

Let's check these tables and see if we can tell linear functions from non-linear functions.

The first one is

  • x values: -1, 0, 1, 2

- we add 1 each time

  • y values: 8, 5, 2, -1

- we subtract 3 each time

\rule{200}{2}

Let's try the next one:

  • x values: -1, 0, 1, 2

- we add 1 each time

  • y values: 5, 10, 15, 20

- we add 5 each time

\rule{200}{2}

Let's try the third one:

  • x values: -1, 0, 1, 2
  • - we add 1 each time
  • y values: 15, 18, 20, 21

        - we add 3, then 2, then 1..

So this table doesn't represent a linear function.

Let's check the fourth one:

  • x values: -1, 0, 1, 2

- we add 1 each time

  • y values: 1, 2, 3, 4

- we add 1 each time

Thus, Option C is the right option.

Hope everything is clear.

Let me know if you have any questions!

Always remember: Knowledge is power!

4 0
2 years ago
The integer<br> is neither positive nor negative.
Artist 52 [7]

Answer:

false

Step-by-step explanation:

an integer is any number greater or less than 0

8 0
3 years ago
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