Question

?? “solve the missing elements for each problem. use 3.14 for area

Answer 1

Answer:

Problem 4:

Radius = 11 cm.

Circumference = 69.08 cm.

Problem 5:

Radius = 14 mm.

Circumference = 87.92 mm.

Problem 6:

Radius = 9 inches.

Circumference = 56.52 inches.

Problem 7:

Diameter = 32 ft.

Circumference = 100.48 ft.

Problem 8:

Diameter = 26 yards.

Circumference = 81.64 yards.

Problem 9:

Diameter = 12 cm.

Circumference = 37.68 cm.

Step-by-step explanation:

Problem 4:

Given:

Diameter GH = 22 cm

We need to find the radius EF and Circumference of the circle.

Now radius is given by half of the diameter

Also Circumference is given by π times diameter.

Radius EF = $\frac{1}{2}\times Diameter = \frac{1}{2}\times 22 = 11 \ cm$

Circumference = $\pi \times Diameter = 3.14 \times 22 = 69.08\ cm$

Hence Radius = 11 cm

Circumference = 69.08 cm.

Problem 5:

Given:

Diameter OP = 28 mm

We need to find the radius MN and Circumference of the circle.

Now radius is given by half of the diameter

Also Circumference is given by π times diameter.

Radius MN = $\frac{1}{2}\times Diameter = \frac{1}{2}\times 28 = 14 \ mm$

Circumference = $\pi \times Diameter = 3.14 \times 28 = 87.92\ mm$

Hence Radius = 14 mm

Circumference = 87.92 mm.

Problem 6:

Given:

Diameter EF = 18 inches

We need to find the radius CD and Circumference of the circle.

Now radius is given by half of the diameter

Also Circumference is given by π times diameter.

Radius CD = $\frac{1}{2}\times Diameter = \frac{1}{2}\times 18 = 9 \ in$

Circumference = $\pi \times Diameter = 3.14 \times 18 = 56.52\ in$

Hence Radius = 9 inches.

Circumference = 56.52 inches.

Problem 7:

Given:

Radius GH = 16 ft

We need to find the Diameter CD and Circumference of the circle.

Now Diameter is given by twice the radius.

Also Circumference is given by π times diameter.

Diameter KJ = $2 \times radius = 2 \times 16 = 32 \ ft$

Circumference = $\pi \times Diameter = 3.14 \times 32 = 100.48\ ft$

Hence Diameter = 32 ft.

Circumference = 100.48 ft.

Problem 8:

Given:

Radius LM = 13 yards

We need to find the Diameter CD and Circumference of the circle.

Now Diameter is given by twice the radius.

Also Circumference is given by π times diameter.

Diameter NO = $2 \times radius = 2 \times 13 = 26 \ yards$

Circumference = $\pi \times Diameter = 3.14 \times 26 = 81.64\ yards$

Hence Diameter = 26 yards.

Circumference = 81.64 yards.

Problem 9:

Given:

Radius NO = 6 cm

We need to find the Diameter CD and Circumference of the circle.

Now Diameter is given by twice the radius.

Also Circumference is given by π times diameter.

Diameter PQ = $2 \times radius = 2 \times 6 = 12 \ cm$

Circumference = $\pi \times Diameter = 3.14 \times 12 = 37.68\ cm$

Hence Diameter = 12 cm.

Circumference = 37.68 cm.