Determine whether the relationship between the circumfrance of a circle and its diameter is a direct variation. If so, identify
1 answer:
Answer:
The relationship between the circumference of a circle and its diameter represent a direct variation and the constant of proportionality is equal to the constant
Step-by-step explanation:
we know that
A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form
where K is the constant of proportionality
In this problem we know that
The circumference of a circle is equal to
therefore
the relationship between the circumference of a circle and its diameter is a direct variation and the constant of proportionality is equal to the constant
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Answer:
Step-by-step explanation:
Hello!
The variable of interest is
X: The number of emergency service calls made by the volunteer ambulance service of Walterboro, South Carolina for 50 days.
a)
In the first column, you have the possible number of emergency calls made, in the second column, you have the observed absolute frequency (fi) for each value of the variable.
To establish the probability distribution you have to calculate the relative frequency (hi) for each value of X.
The formula for the relative frequency is
hi= fi*n where i= 0, 1, 2, 3, 4
X₁= 0
f₁= 8
h₁= 8/50= 0.16
X₂= 1
f₂= 10
h₂= 0.20
X₃= 2
f₃= 22
h₃= 22/50= 0.44
X₄= 3
f₄= 9
h₄= 9/50= 0.18
X₅= 4
f₅= 1
h₅= 1/50= 0.02
(See attachment)
b)
The variable of interest is a cuantitative discrete variable, so this is an example of a driscrete distribution.
Discrete variables are numerical and take certain numbers within its range of definition, contrary to the continuous variables that can take any value within the range of definition of the variable.
Another example of a discrete variable is "the money", If the variable is "I have at most 10 dollars in my wallet", the range of definition goes from 0 dollars to 10 dollars.
c) To calculate the mean when the data is arranged in a frequency table you have to use the following formula:
X[bar]= ∑Xihi= (0*0.16)+(1*0.2)+(2*0.44)+(3*0.18)+(4*0.02)= 1.7
This means that they expect an average of 1.7 calls per day.
d) The formula for the standard deviation is:
∑X²fi= (0²*8)+(1²*10)+(2²*22)+(3²*9)+(4²*1)= 195
∑Xfi= (0*8)+(1*10)+(2*22)+(3*9)+(4*1)= 85
I hope this helps!
