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ikadub [295]
3 years ago
15

A classic counting problem is to determine the number of different ways that the letters of millennium can be arranged. Find tha

t number. The number of different ways that the letters of millennium can be arranged is
Mathematics
1 answer:
Eddi Din [679]3 years ago
7 0

Answer:

<u>The correct answer is that the number of different ways that the letters of the word "millennium" can be arranged is 226,800</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Number of letters of the word "millennium" = 10

Letters repeated:

m = 2 times

i = 2 times

l = 2 times

n = 2 times

2. The number of different ways that the letters of millennium can be arranged is:

We will use the n! or factorial formula, this way:

10!/2! * 2! * 2! * 2!

(10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1)/(2 * 1) * (2 * 1) * (2 * 1) * (2 *1)

3'628,800/2*2*2*2 = 3'628,800/16 = 226,800

<u>The correct answer is that the number of different ways that the letters of the word "millennium" can be arranged is 226,800</u>

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aliya0001 [1]

The key here is to not worry too much and just follow PEMDAS.

Here we have the expression (5\cdot 7)^2.  Following PEMDAS, we complete the expression inside the parentheses first, or 5\cdot 7 = 35. This gives us (35)^2 or just 35^2.

Hope this helps.

8 0
1 year ago
Using Euler's relation, derive the following relationships:a. Cosθ=½(e^jθ+e^−jθ)b. Sinθ=½(e^jθ−e(^−jθ)
Montano1993 [528]

Answer:

a. cosθ = ¹/₂[e^jθ + e^(-jθ)] b. sinθ = ¹/₂[e^jθ - e^(-jθ)]

Step-by-step explanation:

a.We know that

e^jθ = cosθ + jsinθ and

e^(-jθ) = cosθ - jsinθ

Adding both equations, we have

e^jθ = cosθ + jsinθ

+

e^(-jθ) = cosθ - jsinθ

e^jθ + e^(-jθ) = cosθ + cosθ + jsinθ - jsinθ

Simplifying, we have

e^jθ + e^(-jθ) = 2cosθ

dividing through by 2 we have

cosθ = ¹/₂[e^jθ + e^(-jθ)]

b. We know that

e^jθ = cosθ + jsinθ and

e^(-jθ) = cosθ - jsinθ

Subtracting both equations, we have

e^jθ = cosθ + jsinθ

-

e^(-jθ) = cosθ - jsinθ

e^jθ + e^(-jθ) = cosθ - cosθ + jsinθ - (-jsinθ)

Simplifying, we have

e^jθ - e^(-jθ) = 2jsinθ

dividing through by 2 we have

sinθ = ¹/₂[e^jθ - e^(-jθ)]

4 0
3 years ago
25 POINTS PLZ ANSWER!!!!!!!!!!!!!!!!!!!!!!!!!!
Tatiana [17]
The answer is c!!!!!!!
4 0
3 years ago
Read 2 more answers
Write number in two other forms 40,000+1,000+300+70+8
tankabanditka [31]
1.) 35,000+6,000+65+13
2.) 25,000+ 16,000+11,000+78
8 0
3 years ago
According to the National Education Association (NEA), teachers generally spend more than 40 hours each week working on instruct
abruzzese [7]

Answer:

The median number of hours worked per week for the sample of 13 high school science teachers is 52.

Step-by-step explanation:

Median of a data set:

The median of a data set is the element that separates the lower 50% of the set from the upper 50%.

If the cardinality n of the set is odd, the median is the element at the position (n+1)/2 of the sorted sed.

If the cardinality n of the set is even, the median is the mean between the elements at the position n/2 and (n/2)+1 of the sorted sed.

In this question:

Hours worked for the sample of 13 high school science teachers:

55, 58, 52, 52, 56, 59, 48, 63, 52, 52, 50, 52, 56

Sorting in an ascending way:

48, 50, 52, 52, 52, 52, 52, 55, 56, 56, 58, 59, 63

Cardinality of 13, so odd, the median is the element at the 13+1/2 = 7th position of the sorted set, which is 52.

The median number of hours worked per week for the sample of 13 high school science teachers is 52.

8 0
3 years ago
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