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Katen [24]
3 years ago
6

Hey! please help i’ll give brainliest

Mathematics
1 answer:
Anna11 [10]3 years ago
3 0

Answer: A goverment by people

Step-by-step explanation:

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Please help me with questions 23, 24, and 25
alekssr [168]
Problem 23
A = 40
B = 3x+1
C = 3x+1
B and C are congruent, so they have the same angle measure

The three angles of any triangle add to 180 degrees
A+B+C = 180
40+(3x+1)+(3x+1) = 180
6x+42 = 180
6x = 180-42
6x = 138
x = 138/6
x = 23

Answer: B) 23

============================================================

Problem 24

AB is the midsegment parallel to XY
So AB is half that of XY
AB = (1/2)*XY
AB = (1/2)*28
AB = 14

Answer: B) 14

============================================================

Problem 25

Note the ratio of the given rectangle's sides: 7/12 = 0.583 roughly

Divide the answer choices in a similar fashion
A) 5/7 = 0.714
B) 14/36 = 0.389
C) 21/36 = 0.583
D) 21/48 = 0.4375

We get the same result in choice C as we did in the original rectangle

Answer: C) 21 ft x 36 ft

6 0
3 years ago
Write 3.25 as a mixed number in simplest form.
snow_tiger [21]
3.25 can be re-written as;
=3+0.25
Converting the decimal to a fraction gives;
3+\frac{25}{100}
=Simplify the fraction;
3+\frac{1}{4}
The final answer is;
3\frac{1}{4}

4 0
3 years ago
Read 2 more answers
Write the equation for the hyperbola with foci (–12, 6), (6, 6) and vertices (–10, 6), (4, 6).
fomenos

Answer:

\frac{(x--3)^2}{49} -\frac{(y-6)^2}{32}=1

Step-by-step explanation:

The standard equation of a horizontal hyperbola with center (h,k) is

\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1

The given hyperbola has vertices at (–10, 6) and (4, 6).

The length of its major axis is 2a=|4--10|.

\implies 2a=|14|

\implies 2a=14

\implies a=7

The center is the midpoint of the vertices (–10, 6) and (4, 6).

The center is (\frac{-10+4}{2},\frac{6+6}{2}=(-3,6)

We need to use the relation a^2+b^2=c^2 to find b^2.

The c-value is the distance from the center (-3,6) to one of the foci (6,6)

c=|6--3|=9

\implies 7^2+b^2=9^2

\implies b^2=9^2-7^2

\implies b^2=81-49

\implies b^2=32

We substitute these values into the standard equation of the hyperbola to obtain:

\frac{(x--3)^2}{7^2} - \frac{(y-6)^2}{32}=1

\frac{(x+3)^2}{49} -\frac{(y-6)^2}{32}=1

7 0
3 years ago
What is the sum of the geometric series
Sergio039 [100]
Answer: 2343 / 256

Explanation

I will do this for you in two forms: 1) adding each term, and 2) using the general formula for the sum of geometric series.

1) Adding the terms:

 4
∑ 3 (3/4)^i = 3 (3/4)^0 + 3 (3/4)^1 + 3 (3/4)^2 + 3 (3/4)^3 + 3 (3/4)^4
i=0

= 3 + 9/4 + 27/16 + 81/64 + 243/256 = [256*3 + 27*16 + 64*9 + 4*81 + 243] / 256 =

= 2343 / 256

2) Using the formula:

n-1
∑ A (r^i) = A [1 - r^(n) ] / [ 1 - r]
i=0

Here n - 1 = 4 => n = 5

r = 3/4

A = 3

Therefore the sum is 3 [ 1 - (3/4)^5 ] / [ 1 - (3/4) ] =

= 3 [ 1 - (3^5) / (4^5) ] / [ 1/4 ] = 3 { [ (4^5) - (3^5) ] / (4^5) } / {1/4} =

= (3 * 781) / (4^5) / (1/4) =  3 * 781 / (4^4) = 2343 / 256

So, no doubt, the answer is 2343 / 256
5 0
4 years ago
Jose spent 20% of his allowance on baseball cards. His allowance is $10. How much did he spend on baseball cards?
JulijaS [17]

Answer:

Jose spent $2 on baseball cards.

4 0
3 years ago
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