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vodka [1.7K]
3 years ago
13

Which of the following equations is quadratic?

Mathematics
1 answer:
sergiy2304 [10]3 years ago
3 0
The third option is quadratic

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In the function f(x) = 4(x2 − 6x + ____) + 20, what number belongs in the blank to complete the square?
Shkiper50 [21]
Hello :
f(x) = 4(x2 − 6x + 3² - 3²____) + 20 = 4((x2 − 6x + 3²) - 3²____) + 20<span>
      = 4(x-3)² -36+20
</span>f(x) = 4(x-3)² -16 (vertex form)

6 0
3 years ago
Please help me please!!​
irakobra [83]

Answer:

mok

Step-by-step explanation:

mok

7 0
3 years ago
2(5-3v)+9v=28 step by step please
Irina-Kira [14]
First, distribute the 2 across the parenthesis.
10-3v+9v=28
Combine like terms on the left.
10+6v=28
Start to get the numbers on the right and the v alone on the left by moving the 10 to the right.
6v=28-10
6v=18
Divide to get the v alone.
v=3

Hope that helps.
4 0
3 years ago
How wide is the house?
klemol [59]

Answer:

35.35ft

Step-by-step explanation:

f

7 0
3 years ago
Can you guys help me out on this? I'm still learning sign, cosign, and tangent :)
Yakvenalex [24]

Answer:

\sin d = \frac{4}{7} ; \sin e = \frac{\sqrt{33} }{7}

\cos d = \frac{\sqrt{33} }{7} ; \cos e = \frac{4}{7}

\tan d = \frac{4}{\sqrt{33} } ; \tan e = \frac{\sqrt{33} }{4}

Step-by-step explanation:

For a right angled triangle with one of its angle α (alpha) :-

  • \sin \alpha = \frac{Side \: opposite \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}
  • \cos \alpha  = \frac{Side \: adjacent \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}
  • \tan \alpha  = \frac{Side \: opposite \: to \: \alpha }{Side \: adjacent \: to \: \alpha }

__________________________________________________

According to the question ,

1) When α (alpha) = d

  • \sin d = \frac{4}{7}
  • \cos d = \frac{\sqrt{33} }{7}
  • \tan d = \frac{4}{\sqrt{33} }

2) When α (alpha) = e

  • \sin e = \frac{\sqrt{33} }{7}
  • \cos e = \frac{4}{7}
  • \tan e = \frac{\sqrt{33} }{4}

3 0
3 years ago
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