1. (-4)^-6 * (-4)^7 = (-4)^(-6+7) = (-4)^1 =
B. -4
2. (3*10^6)*(8*10^-4) = (3*8)*10^(6-4) = 24*10^2 =
B. 2.4*10^3
Answer:
i honeslty dont know but good luck have agood night
Step-by-step explanation:
Answer:
First option is the right choice.
Step-by-step explanation:


Best Regards!
Write the highlighted digit's place and value.
3. 567; ones place 4. 6,327; thousandth place
5. 9,325; hundredth place 6. 8,281; tenth place
Write each number in standard form.
7. 5,000 + 500 + 3; 5,503 8. 2,000 + 300 + 20 + 9; 2,329
9. 4,000 + 600 + 8; 4,608 9. 9,000 + 300 + 70 + 2; 9,372
11. 1,221
We know Sierra has the same numbers in the thousandth and ones place, so keep does numbers: 1,?2?
It also has two more hundreds and 3 fewer ones place: Take the original number; 1,024 (Make sure you keep the numbers) into a equation; (1024+200)-3. First Add as it's in the ( ), then subtract, 1,221
I hope I've helped!
There are 6 other positions in the string, each with 26 choices. So if you fix BO as the first two letters, there are

possible strings that you can make.
If BO is at the end of the string, you still have

possible strings.
Together, then, you have

possible strings.