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Anna71 [15]
3 years ago
15

Please help due tmm

Mathematics
1 answer:
MArishka [77]3 years ago
6 0

so get the people down to unit rates first

Natalie= 40 in 9 minutes

Steven= 10 in 3 minutes

multiply Stevens to get it even

so by 3


30 in 9 minutes

so Natalie paints faster

hope I was helpful

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A^2-5a+6<br><br><br> ((factor and solve))
Yakvenalex [24]

Answer: a^2 - 5a + 6

(a-6)(a+1) = 0

Step-by-step explanation:

(a-6) = 0

a=6

(a+1) = 0

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Is triangle A'B'C' a dilation of triangle ABC? Explain.
tresset_1 [31]
<span>C.No, it is not a dilation because the points of the image are not moved away from the center of dilation proportionally. </span>
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The figure is rotated 360° clockwise with the origin as the center of rotation. Which graph represents the rotated figure?
Scilla [17]

Given

The figure is rotated 360° clockwise with the origin as the center of rotation. Which graph represents the rotated figure?

Answer

After the rotation of 360 degrees, a figure comes back to original position

Option A is correct

4 0
10 months ago
1. The mechanics at Lincoln Automotive are reborning a 6 in deep cylinder to fit a new piston. The machine they are using increa
Firdavs [7]

Answer:

0.0239\frac{in^{3}}{min}

Step-by-step explanation:

In order to solve this problem, we must start by drawing a diagram of the cylinder. (See attached picture)

This diagram will help us visualize the problem better.

So we start by determining what data we already know:

Height=6in

Diameter=3.8in

Radius = 1.9 in (because the radius is half the length of the diameter)

The problem also states that the radius will increase on thousandth of an inch every 3 minutes. We can find the velocity at which the radius is increasing with this data:

r'=\frac{1/1000in}{3min}

which yields:

r'=\frac{1}{3000}\frac{in}{min}

with this information we can start solving the problem.

First, the problem wants us to know how fast the volume is increasing, so in order to find that we need to start with the volume formula for a cylinder, which is:

V=\pi r^{2}h

where V is the volumen, r is the radius, h is the height and π is a mathematical constant equal approximately to 3.1416.

Now, the height of the cylinder will not change at any time during the reborning, so we can directly substitute the provided height, so we get:

V=\pi r^{2}(6)

or

V=6 \pi r^{2}

We can now take the derivative to this formula so we get:

\frac{dV}{dt}=2(6)\pi r \frac{dr}{dt}

Which simplifies to:

\frac{dV}{dt}=12\pi r \frac{dr}{dt}

We can now substitute the data provided by the problem to get:

\frac{dV}{dt}=12\pi (1.9) (\frac{1}{3000})

which yields:

\frac{dV}{dt}=0.0239\frac{in^{3}}{min}

3 0
3 years ago
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