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Anna71 [15]
2 years ago
15

Please help due tmm

Mathematics
1 answer:
MArishka [77]2 years ago
6 0

so get the people down to unit rates first

Natalie= 40 in 9 minutes

Steven= 10 in 3 minutes

multiply Stevens to get it even

so by 3


30 in 9 minutes

so Natalie paints faster

hope I was helpful

You might be interested in
Geometry proof<br> help please
Aleks [24]
JK = MN because of Given

∠JLK = ∠MLN because of the vertical angle theorem

JL = LN because of definition of midpoint

ΔJLK = MLN because of SAS

∠K = ∠N because corresponding angles of congruent triangles are congruent.

Hope this helps!<span />
6 0
2 years ago
Read 2 more answers
High school math. Please answer everything in picture. Thank you................................................................
vaieri [72.5K]

Answer:

3) Cubic polynomial with four terms.

4) Linear polynomial with two terms.

5) The zeros are: (1-sqrt(5))/2=-0.618, 1, and (1+sqrt(5))/2=1.618

The y-intercept is y=1

Please, see the attached graph.

6) The zeros are: -1.272, 1.272

The y-intercept is y=1

Please, see the attached graph.

7) Please, see the attached files.

8) Please, see the attached files.

9) Please, see the attached files.

10) Please, see the attached files.


Step-by-step explanation:

3) Degree is the maximun exponent that the variable "x" has, in this case 3, then this is a cubic polynomial, and it has four terms (6x^3, -7x^2, -10x, and -8).


4) Degree is the maximun exponent that the variable "x" has, in this case 1 (x=x^1), then this is a linear polynomial, and it has two terms (-10x, and 10).


5) f(x)=x^3-2x^2+1

Zeros:

f(x)=0→x^3-2x^2+1=0

Factoring:

    x^3-2x^2+0x+1  

 ! 1      -2       0    1

<u>1 !____1____-1_-1</u>

   1      -1        -1   0

   1x^2-1x      -1 = x^2-x-1

x^3-2x^2+1=0→(x-1)(x^2-x-1)=0

The zeros are:

x-1=0→x-1+1=0+1→x1=1

x^2-x-1=0

ax^2+bx+c=0; a=1, b=-1, c=-1

x=(-b+-sqrt(b^2-4ac))/(2a)

x=(-(-1)+-sqrt((-1)^2-4(1)(-1))/(2(1))

x=(1+-sqrt(1+4))/2

x2=(1+-sqrt(5))/2=(1+2.236067978)/2=3.236067978/2=1.618033989=1.618

x=(1-sqrt(5))/2=(1-2.236067978)/2=-1.236067978/2=-0.618033989=-0.618

x3=(1+sqrt(5))/2

The zeros are: (1-sqrt(5))/2=-0.618, 1, and (1+sqrt(5))/2=1.618  

The y-intercept is:

x=0→f(0)=(0)^3-2(0)^2+1→f(0)=0-2(0)+1→f(0)=0-0+1→f(0)=1

The y-intercept is y=1.


6) f(x)=-x^4+x^2+1

Zeros:

f(x)=0→-x^4+x^2+1=0

Factoring: Multiplyng both sides of the equation by -1:

(-1)(-x^4+x^2+1)=(-1)(0)

x^4-x^2-1=0

(x^2)^2-(x^2)-1=0

Changing x^2 by t:

t^2-t-1=0

at^2+bt+c=0; a=1, b=-1, c=-1

t=(-b+-sqrt(b^2-4ac))/(2a)

t=(-(-1)+-sqrt((-1)^2-4(1)(-1))/(2(1))

t=(1+-sqrt(1+4))/2

t1=(1+-sqrt(5))/2=(1+2.236067978)/2=3.236067978/2=1.618033989=1.618

t2=(1-sqrt(5))/2=(1-2.236067978)/2=-1.236067978/2=-0.618033989=-0.618

t^2-t+1=0→(t-1.618)(t-(-0.618))=0→(t-1.618)(t+0.618)=0

and t=x^2, then:

(x^2-1.618)(x^2+0.618)=0

Factoring the first parentheses using a^2-b^2=(a+b)(a-b), with:

a^2=x^2→sqrt(a^2)=sqrt(x^2)→a=x

b^2=1.618→sqrt(b^2)=sqrt(1.618)→b=1.272

(x^2-1.618)(x^2+0.618)=0→(x+1.272)(x-1.272)(x^2+0.618)=0

The zeros are:

x+1.272=0→x+1.272-1.272=0-1.272→x1=-1.272

x-1.272=0→x-1.272+1.272=0+1.272→x2=1.272

The zeros are: -1.272, and 1.272  

The y-intercept is:

x=0→f(0)=-(0)^4+(0)^2+1→f(0)=-0+0+1→f(0)=1

The y-intercept is y=1.

3 0
2 years ago
What is the scale factor, perimeter ratio, surface ratio, and the volume ratio?????????????????????????????
tamaranim1 [39]

Answer:

Scale factor = \frac{4}{9}

Perimeter ratio = 4 : 9

Surface area ratio = 16 : 81

Volume ratio = 64 : 729

Step-by-step explanation:

Volume ratio = \frac{\text{volume of small prism}}{\text{Volume of large prism}}

                      = \frac{128}{1458}

                      = \frac{64}{729}

                      = 64 : 729

Scale factor = \sqrt[3]{\frac{\text{volume of small prism}}{\text{Volume of large prism}}}

                    = \sqrt[3]{\frac{64}{729}}

                    = \frac{4}{9}

Perimeter ratio = Scale factor

                         = \frac{4}{9}

                         = 4 : 9

Surface area ratio = (Scale factor)²

                              = (\frac{4}{9})^{2}

                              = \frac{16}{81}

                              = 16 : 81

3 0
3 years ago
The data set shows the ages of people riding a bus.
likoan [24]

Answer:

<u>The correct answer is B. 36</u>

Step-by-step explanation:

1. Let's review the information given for answering the question correctly:

Data set given:

18

36

11

45

36

19

14

18

36

2. What is the mode for this data set?

Let's recall that the Statistical Mode is the number that  is more frequently repeated in a group of numbers.  If no number is repeated, then there is no mode for the list or set.

In this specific set, we can notice that 18 is repeated two times and 36 is repeated three times. Therefore, the mode for this set of ages of people riding a bus is 36.

<u>The correct answer is B. 36</u>

4 0
3 years ago
If FH = 9x + 15 and GH = 5x + 4,<br> then FG = ?
Tatiana [17]

Answer:

FG = 39

Step-by-step explanation:

From the question given:

FH = 9x + 15

GH = 5x + 4

FG = ?

From the question given above, we can say that G is the midpoint of FH. This implies that:

FH = FG + GH

With the above idea in mind, we can obtain FG as follow:

FH = 9x + 15

GH = 5x + 4

FG = ?

FH = FG + GH

9x + 15 = FG + 5x + 4

Rearrange

FG = 9x + 15 - 5x - 4

FG = 9x - 5x + 15 - 4

FG = 4x + 11

Next, we shall determine the value of x. This can be obtained as follow:

Since G is the midpoint of FH, it therefore means that FG and GH are equal i.e

FG = GH

With the above idea in mind, we can obtain the value of x as follow:

FG = 4x + 11

GH = 5x + 4

FG = GH

4x + 11 = 5x + 4

Collect like terms

11 - 4 = 5x - 4

7 = x

x = 7

Thus, we can obtain the value of FG as follow:

FG = 4x + 11

x = 7

FG = 4x + 11

FG = 4(7) + 11

FG = 28 + 11

FG = 39

***Check ***

FH = 9x + 15

x = 7

FH = 9(7) + 15 = 63 + 15 = 78

GH = 5x + 4

x = 7

GH = 5(7) + 4 = 35 + 4 = 39

FG = 4x + 11

x = 7

FG = 4(7) + 11 = 28 + 11 = 39

FH = FG + GH

FH = 78

FG = 39

GH = 39

FH = FG + GH

78 = 39 + 39

78 = 78

4 0
3 years ago
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