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bogdanovich [222]
3 years ago
9

Which ordered pair is a solution of the equation y = x - 3? (-2, 5) (-5, 2) (2, 5) (5, 2)

Mathematics
1 answer:
IceJOKER [234]3 years ago
5 0
2=5-3 so the answer is (2, 5)
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The complex solutions of which equation have a real component of 4.
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Answer:

A.

Step-by-step explanation:

I just did this problem and guessed correctly.

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What is g(21) equal to?<br><br> g(t) = t-6/3<br><br> g(21) = [1]
Igoryamba

You have to plug the given input in the formula: if you substitute t with 21 you have

g(t) = \dfrac{t-6}{3} \implies t(21) = \dfrac{21-6}{3}=\dfrac{15}{3}=5

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Which system of inequalities is shown in the graph?
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7 0
3 years ago
Solve the system using elimination: -3x - 3y = 12 -9x + 3y = -24<br><br>The answer is not (-1,-3)
FinnZ [79.3K]

Answer:

{x = 1, y = -5

Step-by-step explanation:

Solve the following system:

{-3 x - 3 y = 12 | (equation 1)

{3 y - 9 x = -24 | (equation 2)

Swap equation 1 with equation 2:

{-(9 x) + 3 y = -24 | (equation 1)

{-(3 x) - 3 y = 12 | (equation 2)

Subtract 1/3 × (equation 1) from equation 2:

{-(9 x) + 3 y = -24 | (equation 1)

0 x - 4 y = 20 | (equation 2)

Divide equation 1 by 3:

{-(3 x) + y = -8 | (equation 1)

{0 x - 4 y = 20 | (equation 2)

Divide equation 2 by 4:

{-(3 x) + y = -8 | (equation 1)

{0 x - y = 5 | (equation 2)

Multiply equation 2 by -1:

{-(3 x) + y = -8 | (equation 1)

{0 x+y = -5 | (equation 2)

Subtract equation 2 from equation 1:

{-(3 x)+0 y = -3 | (equation 1)

{0 x+y = -5 | (equation 2)

Divide equation 1 by -3:

{x+0 y = 1 | (equation 1)

{0 x+y = -5 | (equation 2)

Collect results:

Answer:  {x = 1 , y = -5

5 0
3 years ago
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