Vcylinder=hpir^2
Vcone=(1/3)hpir^2
d/2=r
so
1.
d=8
r=8/2=4
h=3r
h=3(4)
h=12
V=12*3.14*4^2
V=602.88 in^2
2. cone that fits has same base area and therefor same radius
d=6
r=6/2=3
rcone=3
find height of can
V=hpir^2
21=h*3.14*3^2
21=h*3.14*9
0.7431=h
so
cone height=0.7431
radius=3
V=(1/3)(0.7431)(3.14)(3^2)
V=7 cubic units
3.
same base
find dimentions
s=s=s
V=s^3
27=s^2
3=s
Vsquarepyramid=(1/3)hs^2
s=legnth of base
h=height
h=side
V=(1/3)(3)(3^2)
V=9
C
1. 602.88 in^2
2. 7 cubic units
3. 9cm^3, C
If my maths are correct it would be $3,000
Answer:
52.36
Step-by-step explanation:
Formula to find volume in a cone is
V = pi • radius^2 h/3
So we fill in the numbers
V = pi •
the radius is half of diameter,
The diameter is 5
So it's
V = pi • 2.5
since it's half of 5
V = pi • 2.5^2 h/3
the height is 8 so we fill it in
V = pi • 2.5^2 8/3
When calculated, you get..
52.36
Answer:
B. n || m
Step-by-step explanation:
Lines m and n are intersected by tranversal k. Alternate exterior angles 1 and 2 are congruent. Therefore, lines m and n are parallel. That is the only conclusion you can draw.
Answer: B. n || m
