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choli [55]
3 years ago
13

A recipe for whole grain bread calls for 1 oz of rye flour for every 3 oz of whole wheat flour How many ounces of each kind of f

lour should be used to make a loaf of
bread weighing 22 oz?
Mathematics
1 answer:
natali 33 [55]3 years ago
3 0

Given :

A recipe for whole grain bread calls for 1 oz of rye flour for every 3 oz of whole wheat flour.

To Find :

How many ounces of each kind of flour should be used to make a loaf of

bread weighing 22 oz.

Solution :

It is given that ratio of rye and whole wheat flour is 1 : 3.

Let, amount of rye flour is x and amount of whole wheat flour is 3x.

So, x + 3x = 22

4x = 22

x = 5.5 oz

3x = 16.5 oz

Therefore, amount of rye flour and whole wheat flour is 5.5 and 16.5 oz respectively.

Hence, this is the required solution.

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Which<br>expression is equivalent to 1/5m -20​
muminat

There are infinite equivalent expressions. Here are some:

1/5(m-100)

20(1/100m-1)

1/5m-(4•5)

If you expand any of these or any of the terms, you will get an equivalent expression.

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3 years ago
What is the value of X?
Leviafan [203]

Answer:

w = 31

Step-by-step explanation:

To find the value of w:

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w + w + (4w-6) =180

Add like terms

6w-6 = 180

Add 6 to each side

6w -6+6 =180+6

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Divide each side by 6

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3 years ago
I REALLY NEED SOME HELP! I CANT FAIL THIS!! PLEASE!!
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Answer:

1: D

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Step-by-step explanation:

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2 years ago
What facts are required in order to conclude that m∠ADE = m∠ABC?
mariarad [96]

Answer:

The correct option is;

DE = 2·(BC), AD = 2·(AB), and AE = 2·(AC)

Step-by-step explanation:

Given that we have;

1) The side AD of the angle m∠ADE corresponds to the side AB of the angle m∠ABC

2) The side DE of the angle m∠ADE corresponds to the side BC of the angle m∠ABC

3) The side AE of the angle m∠ADE corresponds to the side AC of the angle m∠ABC

Then when we have DE = 2·(BC), AD = 2·(AB), and AE = 2·(AC), we have by sin rule;

AE/(sin(m∠ADE)) = 2·(AC)/(sin(m∠ABC)) = AE/(sin(m∠ABC))

∴ (sin(m∠ADE)) = (sin(m∠ABC))

m∠ADE) = m∠ABC).

3 0
3 years ago
Suppose that your business is operating at the 4.5-Sigma quality level. If projects have an average improvement rate of 50% annu
Luda [366]

Answer:

  11.75 years

Step-by-step explanation:

If we ignore the fact that "6-sigma" quality means the error rate corresponds to about -4.5σ (3.4 ppm) and simply go with ...

  P(z ≤ -6) ≈ 9.86588×10^-10

and

  P(z ≤ -4.5) ≈ 3.39767×10^-6

the ratio of these error rates is about 0.000290372. We're multiplying the error rate by 0.5 each year, so we want to find the power of 0.50 that gives this value:

  0.50^t = 0.000290372

  t·log(0.50) = log(0.00290372) . . . . take logarithms

  t = log(0.000290372)/log(0.50) ≈ -3.537045/-0.301030

  t ≈ 11.75

It will take about 11.75 years to achieve Six Sigma quality (0.99 ppb error rate).

_____

<em>Comment on Six Sigma</em>

A 3.4 ppm error rate is customarily associated with "Six Sigma" quality. It assumes that the process may have an offset from the mean of up to 1.5 sigma, so the "six sigma" error rate is P(z ≤ (1.5 -6)) = P(z ≤ -4.5) ≈ 3.4·10^-6.

Using that same criteria for the "4.5-Sigma" quality level, we find that error rate to be P(z ≤ (1.5 -4.5)) = P(z ≤ -3) ≈ 1.35·10^-3.

Then the improvement ratio needs to be only 0.00251699, and it will take only about ...

  t ≈ log(0.00251699)/log(0.5) ≈ 8.6 . . . . years

5 0
3 years ago
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