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LuckyWell [14K]
3 years ago
7

Help me?????? please

Mathematics
1 answer:
lutik1710 [3]3 years ago
4 0
1. Match to B
2. Match to A
3. Match to D
4. Prime

Hope it helps!
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Find the hypotenuse
Anika [276]
A^2+b^2=c^2
11^2+4^2=c^2
121+16=c^2
137=c^2
\sqrt{137}  =  \sqrt{c}
11.70=c

8 0
3 years ago
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A giant bamboo plant grew an average of 18 centimeters per year.The botanist started measuring the plant when it was 5 centimete
Anastaziya [24]
H=height
y=number of years.

we have the next expresion:
h(y)=my+b  

m=the slope of the line, in this case, the slope is equal to "18"; (18 cm/ year).
b=the initial heigth, in this case, the initial heigth is equal to "5" (5 cm).

Therefore, our  expression will be:
h(y)=18y +5

answer: h(y)=18y+5


7 0
3 years ago
The value of n is a distance of 1.5 units from -2 on a number line . Click on the number line yo show the possible vault of n.
STatiana [176]

Answer:

I don't know

Step-by-step explanation:

I don't know

5 0
3 years ago
4y-5x>20 how do i graph this
Romashka [77]
It is a diagonal line that intersects the y-axis at y=5 and it intersects the x-axis at x=-4. The slope of the graph is 5/4. 
3 0
3 years ago
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Of the 2,598,960 different five-card hands possible from a deck of 52 playing cards, how many would contain all black cards.
kumpel [21]

Answer: 65,780

Step-by-step explanation:

When we select r things from n things , we use combinations and the number of ways to select r things = ^nC_r=\dfrac{n!}{(n-r)!r!}

Given : The total number of playing cards in a deck = 52

The number of different five-card hands possible from a deck = 2,598,960

In a deck , there are 26 black cards and 26 red cards.

The number of ways to select 5 cards from 26 cards = ^{26}C_{5}=\dfrac{26!}{(26-5)!5!}

=\dfrac{26\times25\times24\times23\times22\times21!}{21!(120)}=65780

Hence, the number of different five-card hands possible from a deck of 52 playing cards such that all are black cards = 65,780

3 0
3 years ago
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