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3 years ago

Can someone help me with this

Mathematics

1 answer:

zubka84 [21]3 years ago

8 0

Answer:

qr=1.3

Step-by-step explanation:

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What is the simplest form of this expression –x3(3x+1)-2x4?

Orlov [11]

Answer:

x^4+x^3

Step-by-step explanation:

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3 years ago

Read 2 more answers

Please help with 6-38 and give explanation on how you did it

MAXImum [283]

If you do 6-8 you get -2 so all you have to do is add the 3 and its negative. the answer is .............-32

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3 years ago

Brian is walking 2 3/4 of a mile everyday. He does this for one week.

laiz [17]

Answer:

1. 11/4

2. 19 1/4

Step-by-step explanation:

To change into an improper fraction:

((2 times 4)+3)/4

=11/4

To calculate total distance:

(11/4) times 7

=77/4

=19 1/4

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3 years ago

Explain how to do this problem

Darina [25.2K]

The lines are parallel that mean that they both have a slope of 2

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2 years ago

Find all roots: x^3 + 7x^2 + 12x = 0 Show all work and check your answer.

Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

Solution:

We have been given a cubic polynomial.

$x^{3}+7 x^{2}+12 x=0$

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

$x^{3}+7 x^{2}+12 x=0$

$x\left(x^{2}+7 x+12\right)=0$ ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

$x^{2}+7 x+12=0$

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

$\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}$

Therefore, the two roots are:

$\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}$

And,

$\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}$

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0

3 years ago