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sineoko [7]
3 years ago
10

What are the ordered pairs of the solutions for this system of equations? y = -x2 + 2 y = x​

Mathematics
1 answer:
sergiy2304 [10]3 years ago
5 0

Answer:

The solutions of this system of equations are (-2, -2) and (1, 1).

Step-by-step explanation:

Let be the following system of equations:

y = -x^{2}+2 (1)

y = x (2)

(2) in (1):

y = -y^{2}+2

y^{2}+y-2 = 0

This polynomial can be solved analytically by Quadratic Formula:

y_{1} = 1, y_{2} = -2

Hence, the solutions of this system of equations are (-2, -2) and (1, 1).

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Simplify the expression to a polynomial in standard form: (4x+5) (x^2-3x-2) PLEASE HLEP
pickupchik [31]

Answer:

4x^3-7x^2-23x-10

Step-by-step explanation:

So we have the expression:

(4x+5)(x^2-3x-2)

Distribute. Multiply (4x+5) to each term:

(x^2)(4x+5)+(-3x)(4x+5)+(-2)(4x+5)

Distribute:

=(4x^3+5x^2)+(-12x^2-15x)+(-8x-10)

Combine like terms:

=(4x^3)+(5x^2-12x^2)+(-15x-8x)+(-10)

Add and simplify:

=4x^3-7x^2-23x-10

And this is in descending order, so it's in standard form.

7 0
3 years ago
What number can replace the n in n/12 to make it equivalent to 1/2 ?<br> 6<br> 8<br> 9<br> 10
Ierofanga [76]

Answer:

i believe the answer is 6.

4 0
3 years ago
Read 2 more answers
The average score of all golfers for a particular course has a mean of 75 and a standard deviation of 4. Suppose 64 golfers play
Vilka [71]

Answer:

0.0228 = 2.28% probability that the average score of the 64 golfers exceeded 76.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 75, \sigma = 4, n = 64, s = \frac{4}{\sqrt{64}} = 0.5

Find the probability that the average score of the 64 golfers exceeded 76.

This is 1 subtracted by the pvalue of Z when X = 64.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{76 - 75}{0.5}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

0.0228 = 2.28% probability that the average score of the 64 golfers exceeded 76.

6 0
3 years ago
Solve the equation.
djverab [1.8K]
(y - 5)/3 = 1
y - 5 = 3 x 1 = 3
y = 3 + 5 = 8

6x + 29 = 5
6x = 5 - 29 = -24
x = -24/6 = -4
7 0
3 years ago
Read 2 more answers
Please help !<br> If you can
iren2701 [21]

Answer:

80 degrees

Step-by-step explanation:

We can use the Central Angle Theorum, which states that if the vertex of the angle is the center of the circle, then the arc is the same measurement as the angle.

In this case, m<COB is 80 degrees, and the vertex is the center of the circle, which means that measure of arc CB is also 80 degrees

8 0
3 years ago
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